The solubility of CuBr ( s ) at equilibrium to be calculated. Concept introduction: The constant K sp is known as solubility product or solubility product constant. It is equilibrium constant and for a given solid, it has a particular value at a given temperature. However, the solubility is equilibrium position. The solubility product expression comprises of product of the ion concentrations.
The solubility of CuBr ( s ) at equilibrium to be calculated. Concept introduction: The constant K sp is known as solubility product or solubility product constant. It is equilibrium constant and for a given solid, it has a particular value at a given temperature. However, the solubility is equilibrium position. The solubility product expression comprises of product of the ion concentrations.
Interpretation: The solubility of
CuBr(s) at equilibrium to be calculated.
Concept introduction: The constant
Ksp is known as solubility product or solubility product constant. It is equilibrium constant and for a given solid, it has a particular value at a given temperature. However, the solubility is equilibrium position. The solubility product expression comprises of product of the ion concentrations.
(b)
Interpretation Introduction
Interpretation: The concentration of
Br− at equilibrium to be calculated.
Concept introduction: The constant
Ksp is known as solubility product or solubility product constant. It is equilibrium constant and for a given solid, it has a particular value at a given temperature. However, the solubility is equilibrium position. The solubility product expression comprises of product of the ion concentrations.
(c)
Interpretation Introduction
Interpretation: The concentration of
CN− at equilibrium to be calculated.
Concept introduction: The constant
Ksp is known as solubility product or solubility product constant. It is equilibrium constant and for a given solid, it has a particular value at a given temperature. However, the solubility is equilibrium position. The solubility product expression comprises of product of the ion concentrations.
Cu2+(aq) + H2O(l) ⇌ CuOH+(aq) + H+(aq) Keq = 1.2 x 10−8
A 1.00 M solution of copper(II) nitrate is created and the system shown above reaches equilibrium. What happens to the pH of the system if more CuOH+ is added after reaching equilibrium?
The pH of the system will not change because of the small size of K.
The pH of the system will increase because of the increased concentration of CuOH+.
The pH of the system will increase as the reverse reaction proceeds at a faster rate to reestablish equilibrium.
The pH of the system will decrease as the forward reaction proceeds at a faster rate to reestablish equilibrium.
理 E
The equilibrium concentration of hydroxide ion in a saturated cobalt(II) hydroxide solution is
Given the equation:
Ag+(aq)+2NH3(aq)⟶[Ag(NH3)2]+(aq) ?f=2.00×10^7
determine the concentration of NH3(aq) that is required to dissolve 295 mg of AgCl(s) in 100.0 mL of solution. The ?sp of AgCl is 1.77×10^−10.
I've worked this through several times, but I am just not coming up with the right answer! Thanks :)
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell