(a) Interpretation: The formula for the percent ionization of the weak acid needs to be derived using the appropriate assumptions. %ionized = 100 1 + 10 ( pK-pH ) Concept introduction: The pH of the solution is used to measure the hydrogen ion’s molar concentration in the solution, and it is the measure of basicity or acidity of a solution. For any solution, if pH is less than 7 then it is acidic. pH equal to 7 is neutral and solution having pH greater than 7 is basic. The hydrogen ion’s concentration is greater than hydroxide ions in an acidic solution.
(a) Interpretation: The formula for the percent ionization of the weak acid needs to be derived using the appropriate assumptions. %ionized = 100 1 + 10 ( pK-pH ) Concept introduction: The pH of the solution is used to measure the hydrogen ion’s molar concentration in the solution, and it is the measure of basicity or acidity of a solution. For any solution, if pH is less than 7 then it is acidic. pH equal to 7 is neutral and solution having pH greater than 7 is basic. The hydrogen ion’s concentration is greater than hydroxide ions in an acidic solution.
Solution Summary: The author explains the formula for the percent ionization of the weak acid using the appropriate assumptions.
The formula for the percent ionization of the weak acid needs to be derived using the appropriate assumptions.
%ionized = 1001+10(pK-pH)
Concept introduction:
The pH of the solution is used to measure the hydrogen ion’s molar concentration in the solution, and it is the measure of basicity or acidity of a solution. For any solution, if pH is less than 7 then it is acidic. pH equal to 7 is neutral and solution having pH greater than 7 is basic. The hydrogen ion’s concentration is greater than hydroxide ions in an acidic solution.
Interpretation Introduction
(b)
Interpretation:
The percentage ionization of formic acid solution, HCOOH (aq) needs to be determined, having pH of 2.50.
Concept introduction:
As per the Bronsted-Lowry theory of bases and acids, proton acceptors are bases and proton donors are acids. Molecules which can either accept or donate the proton are known as amphiprotic. So, an amphiprotic act as either base or acid. Hydrogen sulfate ion, hydrogen carbonate ion, amino acids and water are common illustrations of amphiprotic molecules because they might donate the proton. Moreover, all of the amphiprotic species have hydrogen atom.
Interpretation Introduction
(c)
Interpretation:
The value of Ka of a 0.150 M solution of propanoic acid with pH 2.85 needs to be determined.
CH3CH2CO2H+H2O→H3O++CH3CH2CO2−
Concept introduction:
As per the Bronsted-Lowry theory of bases and acids, proton acceptors are bases and proton donors are acids. Molecules which can either accept or donate the proton are known as amphiprotic. So, an amphiprotic act as either base or acid. Hydrogen sulfate ion, hydrogen carbonate ion, amino acids and water are common illustrations of amphiprotic molecules because they might donate the proton. Moreover, all of the amphiprotic species have hydrogen atom.
5.
Please consider the Newman projection of tartaric acid drawn below as an eclipsed
conformer (1). Please draw the most stable conformer and two intermediate energy conformers
noting that staggered conformers are lower in energy than eclipsed forms even if the staggered
conformers have gauche relationships between groups. [Draw the substituents H and OH on the front
carbons and H, OH and CO₂H on the back carbons based on staggered forms. -CO₂H is larger than -OH.]
OH
COH
ICOOH
COOH
COOH
1
2
COOH
COOH
3
4
Staggered
Staggered
Staggered (most stable)
Indicate the number of each conformer above (1, 2, 3 and 4) that corresponds to the relative energies
below.
Ref=0
Rotation
6. (60 points)
a. Are compounds 1 and 2 below enantiomers, diastereomers or identical?
OH
OH
HO
HO
LOH
HO
HO
OH
2
OH
OH
b. Please complete the zig-zag conformation of the compound
(3R,4S)-3,4-dichloro-2,5-dimethylhexane by writing the respective atoms in the boxes.
3.
The plutonium isotope with 144 neutrons
Enter the chemical symbol of the isotope.
The mass ratio of sodium to fluorine in sodium fluoride is 1.21:1. A sample of sodium fluoride produced 26.1 gg of sodium upon decomposition. How much fluorine was formed?
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