Carbon monoxide is toxic because it bonds much more strongly to the iron in hemoglobin (Hgb) than does O 2 . Consider the following reactions and approximate standard free energy changes: Hgb + O 2 → HgbO 2 Δ G ∘ = − 70 KJ Hgb + CO → HgbCO Δ G ∘ = − 80 KJ Using these data, estimate the equilibrium constant value at 25°C for the following reaction: HgbO 2 + CO ⇌ HgbCO + O 2
Carbon monoxide is toxic because it bonds much more strongly to the iron in hemoglobin (Hgb) than does O 2 . Consider the following reactions and approximate standard free energy changes: Hgb + O 2 → HgbO 2 Δ G ∘ = − 70 KJ Hgb + CO → HgbCO Δ G ∘ = − 80 KJ Using these data, estimate the equilibrium constant value at 25°C for the following reaction: HgbO 2 + CO ⇌ HgbCO + O 2
Solution Summary: The author explains that the value of K is to be calculated at given temperature for the reaction between HgbO_
Carbon monoxide is toxic because it bonds much more strongly to the iron in hemoglobin (Hgb) than does O2. Consider the following reactions and approximate standard free energy changes:
Hgb
+
O
2
→
HgbO
2
Δ
G
∘
=
−
70
KJ
Hgb
+
CO
→
HgbCO
Δ
G
∘
=
−
80
KJ
Using these data, estimate the equilibrium constant value at 25°C for the following reaction:
Name the molecules & Identify any chiral center
CH3CH2CH2CHCH₂CH₂CH₂CH₂
OH
CH₂CHCH2CH3
Br
CH3
CH3CHCH2CHCH2CH3
CH3
Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electrons-pushing arrows for the following reaction or mechanistic step(s).
Chapter 16 Solutions
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