Chapter 16, Problem 85E

Interpretation Introduction

Interpretation:

The volume in milliliters of the $\text{16}\text{M}$ ${\text{HNO}}_{\text{3}}$ used for preparation of $\text{7}{\text{.50×10}}^{\text{2}}\text{mL}$ of $\text{0}\text{.69}\text{M}$ ${\text{HNO}}_{\text{3}}$ is to be calculated.

Concept introduction:

Molarity is defined as the number of moles of solute present in one liter of solution. This can be expressed by the relation given below.

$\text{M}=\frac{\text{n}}{\text{V}\left(\text{in L}\right)}$

On dilution, the molarity and the volume of the final solution are calculated by the relation given below.

${\text{M}}_{\text{c}}{\text{V}}_{\text{c}}={\text{M}}_{\text{d}}{\text{V}}_{\text{d}}$