Chapter 16, Problem 40E

Interpretation Introduction

Interpretation:

The molarity of solution when $\text{1}\text{.2}\times {\text{10}}^{\text{2}}\text{g}$ of sodium thiosulfate is dissolved in $\text{1}\text{.25}\times {\text{10}}^3\text{mL}$ water is to be calculated.

Concept Introduction:

Molarity is defined as the number of moles present in one liter of solution. General expression is shown below.

$\text{Molarity}=\frac{\text{Moles}\text{of}\text{solute}}{\text{Volume}\text{of}\text{solution}}$

Measuring unit of molarity is $\text{mol}/\text{L}$ or $\text{molar}\left(\text{M}\right)$.