Horizons: Exploring the Universe (MindTap Course List)
14th Edition
ISBN: 9781305960961
Author: Michael A. Seeds, Dana Backman
Publisher: Cengage Learning
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Textbook Question
Chapter 16, Problem 7P
The smallest detail visible through Earth-based telescopes is about 1 arc second in diameter. What size object would this represent on Earths Moon? (Hint: Use the small-angle formula in Reasoning with Numbers 3-1.)
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At an average opposition, the Earth and Mars are separated by 0.52 AU. Suppose an astronomer
observes Mars at opposition and that seeing blurs the images to a resolution of 1.0 seconds of arc.
What is the smallest surface feature the astronomer would be able to resolve on Mars? How does
this size compare with the diameter of Mars?
The Mars Robotic Lander for which we are making these calculations is designed to return samples of rock from Mars after a long time of collecting samples, exploring the area around the landing site, and making chemical analyses of rocks and dust in the landing area. One synodic period is required for Earth to be in the same place relative to mars as when it landed.
Calculate the synodic period (in years) using the following formula:
1/Psyn = (1/PEarth) - (1/PMars)
where PEarth is the sidereal period of the Earth (1 year) and PMars is the sidereal period of Mars.
If 3/4 of a Martian year was spent collecting samples and exploring the terrain around the landing site, calculate how long the Mars Robotic Lander expedition took!
Chapter 16 Solutions
Horizons: Exploring the Universe (MindTap Course List)
Ch. 16 - Why would you include the Moon in a comparison of...Ch. 16 - In what ways is Earth unique among the Terrestrial...Ch. 16 - What are the four stages of planetary development?Ch. 16 - How do you know that Earth differentiated?Ch. 16 - How are earthquakes in Hawaii different from those...Ch. 16 - Prob. 6RQCh. 16 - How do island chains located in the centers of...Ch. 16 - Prob. 8RQCh. 16 - H does the increasing abundance of CO2 in Earth’s...Ch. 16 - Why would a decrease in the density of the ozone...
Ch. 16 - Prob. 11RQCh. 16 - Prob. 12RQCh. 16 - Prob. 13RQCh. 16 - How Do We Know? Why is heat flow the key to...Ch. 16 - How Do We Know? In what ways have scientists been...Ch. 16 - Prob. 1DQCh. 16 - Prob. 2DQCh. 16 - Assume P waves travel at 10 km/s and S waves...Ch. 16 - Earth’s metallic core has about 55% of the...Ch. 16 - Prob. 3PCh. 16 - Prob. 4PCh. 16 - Prob. 5PCh. 16 - Earth is four times lager in diameter than its...Ch. 16 - The smallest detail visible through Earth-based...Ch. 16 - Prob. 1LTLCh. 16 - Prob. 2LTLCh. 16 - Prob. 3LTLCh. 16 - Prob. 4LTLCh. 16 - Prob. 5LTL
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- The smallest detail visible through Earth-based telescopes is about 1 arc second in diameter. What linear size is this on the Moon? (Hint: Use the small-angle formula, Eq. 3-1.)arrow_forwardWhat is the maximum angular diameter of the dwarf planet Ceres when it is closest to Earth? Could Earth-based telescopes detect surface features? Could the Hubble Space Telescope? (Hint: Use the small-angle formula, Eq. 3-1.) (Notes: Ceress average distance from the Sun is 2.8 AU and its diameter is 950 km. The best angular resolution of Earth-based telescopes at visual wavelengths is about 1 arc second and of Hubble about 0.1 arc second.)arrow_forwardAstronomers are able to use techniques like measuring the Question Blank 1 of 2 (hint: two words) of a surface to determine the relative age of various parts of that surface. However, if they want a(n) Question Blank 2 of 2 (hint: one word) age of the surface, they need to collect surface samples and then radiometrically date them to get a more exact measurement.arrow_forward
- The Hubble Space Telescope has a resolution of about 0.05 arc second. What is the smallest object it could see on the surface of the Moon? Give your answer in meters.arrow_forwardThe diameter of the earth’s moon 2159is miles. The diameter of Jupiter is 86881miles. How many of earth’s moons could fit across the diameter of Jupiter? Round your answer to the nearest whole number.arrow_forwardVenus can be as bright as apparent magnitude -4.7 when at a distance of about 1 AU. How many times fainter would Venus look from a distance of 5 pc? Assume Venus has the same illumination phase from your new vantage point. (Hints: Recall the inverse square law; also, review the definition of apparent visual magnitudes. ote: 1 pc = 2.1 x 10° AU). times fainter What would its apparent magnitude be? Need Help? Read Itarrow_forward
- The smallest detail visible through a Earth-based telescope is about 1.00 arcsecond in diameter. Use the small angle formula to determine to the right number of significant figures the size of the object in meters this would represent on Mars as it is at the closest distance from Earth. (??????? ???????? (arc−seconds)2.06×105=?????? ??????????????? ; ???−????????????−????=5.46×105 ??).arrow_forwardThe unaided human eye has a resolution of about 100 arc seconds in bright lighting conditions. Could someone looking out the command module window have seen the astronauts on the Moon yes or no?arrow_forwardWhat is the maximum angular diameter of Venus as seen from Earth? (Hint: Use the small-angle formula, Eq. 3-1.) (Note: Necessary data to derive the distance between the objects in that situation are given in the Celestial Profiles for Earth in Chapter 19 and Venus in this chapter.)arrow_forward
- Venus can be as bright as apparent magnitude −4.7 when at a distance of about 1 AU. How many times fainter would Venus look from a distance of 7 pc? Assume Venus has the same illumination phase from your new vantage point. (Hints: Recall the inverse square law; also, review the definition of apparent visual magnitudes. Note: 1 pc = 2.1 ✕ 105 AU). [fill in the blank] times fainter What would its apparent magnitude be?arrow_forward6arrow_forward2arrow_forward
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