Why the pH of 1.00 × 10 − 7 M HCl is not exactly 7.00 should be explained. Concept Introduction: The concentration of hydrogen ions in a solution determines the acidity of a solution. If concentration of hydrogen ion is more than the solution is more acetic, if it is low, solution is less acidic. The pH of solution is defined as negative log of hydrogen ion concentration thus, it can be calculated as follows: p H = − log H + Here, H + is concentration of hydrogen ion. Similarly, pOH of a solution is defined as negative log of hydroxide ion concentration thus, it can be calculated as follows: p O H = − log OH − Here, OH − is concentration of hydroxide ion. pH and pOH of a solution are related to each other as follows: p H + p O H = 14 .
Why the pH of 1.00 × 10 − 7 M HCl is not exactly 7.00 should be explained. Concept Introduction: The concentration of hydrogen ions in a solution determines the acidity of a solution. If concentration of hydrogen ion is more than the solution is more acetic, if it is low, solution is less acidic. The pH of solution is defined as negative log of hydrogen ion concentration thus, it can be calculated as follows: p H = − log H + Here, H + is concentration of hydrogen ion. Similarly, pOH of a solution is defined as negative log of hydroxide ion concentration thus, it can be calculated as follows: p O H = − log OH − Here, OH − is concentration of hydroxide ion. pH and pOH of a solution are related to each other as follows: p H + p O H = 14 .
Solution Summary: The author explains that the pH of 1.00times 10-7M HCl is not exactly 7.00.
Why the pH of 1.00×10−7 M HCl is not exactly 7.00 should be explained.
Concept Introduction:
The concentration of hydrogen ions in a solution determines the acidity of a solution. If concentration of hydrogen ion is more than the solution is more acetic, if it is low, solution is less acidic.
The pH of solution is defined as negative log of hydrogen ion concentration thus, it can be calculated as follows:
pH=−logH+
Here, H+ is concentration of hydrogen ion.
Similarly, pOH of a solution is defined as negative log of hydroxide ion concentration thus, it can be calculated as follows:
pOH=−logOH−
Here, OH− is concentration of hydroxide ion.
pH and pOH of a solution are related to each other as follows:
Solve for x, where M is molar and s is seconds.
x = (9.0 × 10³ M−². s¯¹) (0.26 M)³
Enter the answer. Include units. Use the exponent key above the answer box to indicate any exponent on your units.
▸ View Available Hint(s)
ΜΑ
0
?
Units
Value
Learning Goal:
This question reviews the format for writing an element's written symbol. Recall that written symbols have a particular format. Written symbols use a form like this:
35 Cl
17
In this form the mass number, 35, is a stacked superscript. The atomic number, 17, is a stacked subscript. "CI" is the chemical symbol for the element chlorine. A general way to show this form is:
It is also correct to write symbols by leaving off the atomic number, as in the following form:
atomic number
mass number Symbol
35 Cl or
mass number Symbol
This is because if you write the element symbol, such as Cl, you know the atomic number is 17 from that symbol. Remember that the atomic number, or number of protons in the nucleus, is what defines the element. Thus, if 17 protons
are in the nucleus, the element can only be chlorine. Sometimes you will only see 35 C1, where the atomic number is not written.
Watch this video to review the format for written symbols.
In the following table each column…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.