It is given that, when sodium chloride is added to a solution of silver nitrate, a white precipitate is formed. This precipitate will be dissolved when ammonia is added to this mixture. Now a pale yellow precipitate will appear when a solution of potassium bromide is added to it. Now this precipitate will be dissolved when sodium thiosulfate is added and finally a yellow precipitate is formed when potassium iodide is added to this solution. The balanced equations are to be stated to explain these observations. The conclusion drawn corresponding to the size of the K sp values for AgCl , AgBr and AgI is to be stated. Concept introduction: The formation of solid in a solution is known as precipitation. Solubility product, K sp , is defined as the concentration of ions in a saturated solution where each ion is raised to the power of their coefficients.
It is given that, when sodium chloride is added to a solution of silver nitrate, a white precipitate is formed. This precipitate will be dissolved when ammonia is added to this mixture. Now a pale yellow precipitate will appear when a solution of potassium bromide is added to it. Now this precipitate will be dissolved when sodium thiosulfate is added and finally a yellow precipitate is formed when potassium iodide is added to this solution. The balanced equations are to be stated to explain these observations. The conclusion drawn corresponding to the size of the K sp values for AgCl , AgBr and AgI is to be stated. Concept introduction: The formation of solid in a solution is known as precipitation. Solubility product, K sp , is defined as the concentration of ions in a saturated solution where each ion is raised to the power of their coefficients.
Solution Summary: The author explains that the formation of solid in a solution is known as precipitation. The balanced equations are to explain these observations.
It is given that, when sodium chloride is added to a solution of silver nitrate, a white precipitate is formed. This precipitate will be dissolved when ammonia is added to this mixture. Now a pale yellow precipitate will appear when a solution of potassium bromide is added to it. Now this precipitate will be dissolved when sodium thiosulfate is added and finally a yellow precipitate is formed when potassium iodide is added to this solution. The balanced equations are to be stated to explain these observations. The conclusion drawn corresponding to the size of the
Ksp values for
AgCl,AgBr and
AgI is to be stated.
Concept introduction:
The formation of solid in a solution is known as precipitation. Solubility product,
Ksp, is defined as the concentration of ions in a saturated solution where each ion is raised to the power of their coefficients.
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Solution
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Use retrosynthetic analysis to suggest two paths to synthesize 2-methyl-3-hexanol using the Grignard reaction. (Click and drag
the appropriate image to the correct position in the reactions.)
Route 1
Aldehyde 1
or
+98
Aldehyde 2
Route 2
Q6
+100
Solved in 1 attempt
Q7
+95
Solved in 2 attempts
Q8
+98
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possible
+
+
Grignard 1
OH
H3O+
Grignard 2
Answer Bank
Q9
+90
MgBr
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possible
CH3CH2CH2MgBr
Q10
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Q11
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?
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in 1 attempt
2-methyl-3-hexanol
CH3CH2MgBr
H
H
о
H
Attempt 3
2) (4 pt) After the reaction was completed, the student collected the following data. Crude
product data is the data collected after the reaction is finished, but before the product
is purified. "Pure" product data is the data collected after attempted purification using
recrystallization.
Student B's data:
Crude product data
"Pure"
product data
after
recrystallization
Crude mass: 0.93 g grey solid
Crude mp: 96-106 °C
Crude % yield:
Pure mass: 0.39 g white solid
Pure mp: 111-113 °C
Pure % yield:
a) Calculate the crude and pure percent yields for the student's reaction.
b) Summarize what is indicated by the crude and pure melting points.