To determine Reynold for the water and air. Explanation Write the expression for the relation for Reynolds number as given as follows. Re = ρ V D μ (I) Here, density of fluid is ρ , velocity is V and dynamic viscosity is μ . Conclusion: Refer to Table B.2, “Physical Properties of Water (SI Units)”, At temperature 30 ° C as, Density of the water is 995.7 kg/m 3 . Dynamics viscosity of water is 7.975 × 10 − 4 N ⋅ s m 2 Substitute 995.7 kg/m 3 for ρ , 3 m/s for V , 4 mm for D , and 7.975 × 10 − 4 N ⋅ s m 2 for μ in equation (I). Re = ( 995.7 kg/m 3 ) ( 3 m/s ) ( 4 mm ) 7.975 × 10 − 4 N ⋅ s m 2 = ( 995.7 kg/m 3 ) ( 3 m/s ) ( 4 mm × 1 m 1000 mm ) 7

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Author: HOCHSTEIN

Publisher: JOHN WILEY+SONS INC.

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Chapter 1.6, Problem 65P

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Reynold for the water and air.

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Chapter 1.6, Problem 64P

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Chapter 1 Solutions

EBK MUNSON, YOUNG AND OKIISHI'S FUNDAME

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