To determine The specific gravity and the specific weight of the whipped cream. Explanation Write the expression of mass of cream ( m c ) . m c = ρ c V cup (I) Here, density of the cream is ρ c and volume of the cup is V c u p . Write the expression of density of whipped cream ( ρ W ) . ρ W = m W V 3 cups (II) Here, mass of the whipped cream is m W and volume of 3 cups of whipped cream is V 3 cups . Write the expression of specific gravity ( S G ) . S G = ρ W ρ H 2 O (III) Here, density of water is ρ H 2 O . Write the expression of specific weight of whipped cream ( γ W ) . γ W = ρ W g (IV) Here, acceleration due to gravity is g . Conclusion: The mass of the cream is equal to the mass of the whipped cream. m c = m W Substitute m c for m W in Equation (II). ρ W = m c V 3 cups (V) Substitute ρ c V cup for m c in Equation (V). ρ W = ρ c V cup V 3 cups (VI) Substitute 1005 kg / m 3 for ρ c in Equation (VI)

8th Edition

ISBN: 9781119547990

Author: HOCHSTEIN

Publisher: JOHN WILEY+SONS INC.

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Chapter 1.4, Problem 41P

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The specific gravity and the specific weight of the whipped cream.

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Chapter 1.4, Problem 40P

Chapter 1.4, Problem 42P

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EBK MUNSON, YOUNG AND OKIISHI'S FUNDAME

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