Chapter 16, Problem 40P

Interpretation Introduction

(a)

Interpretation:

Whether the given compound is water soluble or insoluble needs to be determined.

  

Concept Introduction:

The main rule which is used to determine the solubility of a compound in a given solution is that "like dissolves like". Therefore, the polar compounds will be soluble in polar solvents while the non-polar compounds will be soluble in non-polar solvents.

Interpretation Introduction

(b)

Interpretation:

Whether the given compound is water soluble or insoluble needs to be determined.

  ${\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}\text{CHO}$

Concept Introduction:

The main rule which is used to determine the solubility of a compound in a given solution is that "like dissolves like". Therefore, the polar compounds will be soluble in polar solvents while the non-polar compounds will be soluble in non-polar solvents.

Interpretation Introduction

(c)

Interpretation:

Whether the given compound is water soluble or insoluble needs to be determined.

  ${\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}\text{OH}$

Concept Introduction:

The main rule which is used to determine the solubility of a compound in a given solution is that "like dissolves like". Therefore, the polar compounds will be soluble in polar solvents while the non-polar compounds will be soluble in non-polar solvents.