MATERIALS SCIENCE+ENGINEERING-EPUB CARD
10th Edition
ISBN: 9781119405474
Author: Callister
Publisher: WILEY
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Chapter 16, Problem 3FEQP
To determine
The correct answer for better properties of ceramic-matrix composites when compared to other ceramic material.
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Using a relevant image such as a 3D architectural rendering of a warehouse landscape in Edmond.
A simple beam has a span of 10 m and supports a total uniformly distributed load of 12 kN/m.
Properties of W 480×86:
Property
Value
A = 10800 mm²
bf = 180 mm
tf = 15 mm
Ix = 383.13 × 10⁶ mm⁴
tw = 12 mm
d = 480 mm
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Calculate the maximum shear in the beam in kN.
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Given the properties of the wide flange:
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d = 530 mm
bf = 210 mm
tw = 18 mm
tf = 16 mm
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Compute the value of rₜ, defined as the radius of gyration of the compression flange plus 1/3 of the compression web area about the y-axis.
Given an existing two-story steel structure with interior columns spaced as shown in Fig.2. The columns are spaced at 18 ft in the North-South direction and at 30 ft in the East-West direction. An interior lower-story column is to be removed by adding newsteel girder as shown in Fig. 4. The floor dead loads and the roof dead loads are 70 psfand 18 psf respectively. The floor live loads and the roof live loads are 50 psf and20 psf respectively. All existing steel materials are ASTM A36 steel (Fy=36 ksi). Newgirder is ASTM A992 steel (Fy= 50 ksi). All columns are W8x31. Use the LRFD Method.Assumptions:1- The loads given include column and beam self weights.2- Existing beam and new girder are simply supported at both ends.3- New girder top flange is laterally braced at mid span and at girder ends only.4- Columns are continuous from foundation to roof and are prevented from sway atfloor level and at roof level in both directions.5- Columns are pin supported at foundation, at floor level,…
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