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(a)
Interpretation:
A strip of magnesium metal dissolves rapidly in 6.00 mL of a 0.150 M HCl solution, producing hydrogen gas and magnesium chloride.
Assign oxidation numbers to all of the elements in the reactants and products.
Concept Introduction:
Here are the rules for assigning oxidation number to elements:
- For an element in its free state it is assigned an oxidation number of zero.
- Monatomic ions have oxidation number that is equal to charge of the monatomic ion.
- Alkali metals have +1 oxidation number, alkaline earth metals have +2 oxidation number and halogens are assigned -1 oxidation number.
- In most compounds H is assigned a +1 oxidation number and O is assigned a -2 oxidation number.
- For a neutral compound the summation of oxidation numbers of all elements in the compound is zero.
If the oxidation number of an element increases then it undergoes oxidation and if the oxidation number of the element decreases then it undergoes reduction.
(b)
Interpretation:
To write the balanced chemical equation for the reaction.
Concept Introduction:
In a balanced chemical equation for a reaction the number of atoms of each element is equal on both side of the reaction.
(c)
Interpretation:
To find the oxidizing agent.
Concept Introduction:
An oxidizing agent itself gets reduced as it oxidizes other substances. An oxidizing agent accepts electrons.
(d)
Interpretation:
To find the reducing agent.
Concept Introduction:
A reducing agent itself gets oxidized as it reduces other substances. A reducing agent losses electrons.
(e)
Interpretation:
To find the pH of the 0.150 M HCl solution.
Concept Introduction:
(f)
Interpretation:
To find the grams of magnesium that can dissolve in the HCl solution.
Concept Introduction:
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Chapter 16 Solutions
EBK BASIC CHEMISTRY
- Show work. don't give Ai generated solutionarrow_forwardUse the average molarity of acetic acid (0.0867M) to calculate the concentration in % (m/v). Then calculate the % difference between the calculated concentrations of your unknown vinegar solution with the 5.00% (w/v%) vinegar solution (check the formula for % difference in the previous lab or online). Before calculating the difference with vinegar, remember that this %(m/v) is of the diluted solution. It has been diluted 10 times.arrow_forwardWhat deprotonates or what can be formed? Please help me understand the problem.arrow_forward
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