Chapter 16, Problem 23P

To determine

To find: the magnitude and direction of the electric force

Answer to Problem 23P

The magnitude of magnetic force $\mathrm{F}=3.78\times {10}^{-16}\text{N}$

The direction of magnetic force is towards west

Explanation of Solution

Given:

Electric field strength, $\mathrm{E}=2360\text{N}/\text{C}$ that points due east

Formula used:

  $\mathrm{F}=\mathrm{q}\mathrm{E}$

Calculation:

Charge of electron, $\mathrm{q}=-1.602\times {10}^{-19}\text{C}$

Electric force $\text{F}$ related to electric field $\mathrm{E}$ and charge $\mathrm{q}$ as

  $\begin{array}{l}\mathrm{F}=\mathrm{q}\mathrm{E}\\ =\left(-1.602\times {10}^{-19}\text{C}\right)(2360\text{N}/\text{C})\\ =-3.78\times {10}^{-16}\text{N}\end{array}$

Negative sign indicates that the direction of magnetic force is opposite to the eclectic field

Conclusion:

Magnitude of magnetic force $\mathrm{F}=3.78\times {10}^{-16}\text{N}$

Direction of magnetic force is towards west