Applied Statistics in Business and Economics
5th Edition
ISBN: 9780077837303
Author: David Doane, Lori Seward Senior Instructor of Operations Management
Publisher: McGraw-Hill Education
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Chapter 16, Problem 1CR
a.
To determine
Give three advantages of nonparametric tests.
a.
Expert Solution
Explanation of Solution
Advantages of nonparametric tests:
- It is used when the
sample size is small. - It is used for ordinal data.
- Nonparametric tests do not assume normality.
b.
To determine
Give two drawbacks in the data that might force to use a nonparametric test.
b.
Expert Solution
Explanation of Solution
Two drawbacks in the data that might force to use a nonparametric test:
- Small sample size.
- When the sample does not follow normality.
c.
To determine
State the reason why significance in a nonparametric test is convincing.
c.
Expert Solution
Explanation of Solution
Significance in a nonparametric test is convincing because it makes fewer assumptions about the population, when the sample does not follow normality.
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Calculate the 90% confidence interval for the population mean difference using the data in the attached image. I need to see where I went wrong.
Microsoft Excel snapshot for random sampling: Also note the formula used for the last
column
02
x✓ fx =INDEX(5852:58551, RANK(C2, $C$2:$C$51))
A
B
1
No.
States
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1
ALABAMA
Rand No.
0.925957526
3
2
ALASKA
0.372999976
4
3
ARIZONA
0.941323044
5
4 ARKANSAS
0.071266381
Random Sample
CALIFORNIA
NORTH CAROLINA
ARKANSAS
WASHINGTON
G7
Microsoft Excel snapshot for systematic sampling:
xfx INDEX(SD52:50551, F7)
A
B
E
F
G
1
No.
States
Rand No. Random Sample
population
50
2
1 ALABAMA
0.5296685 NEW HAMPSHIRE
sample
10
3
2 ALASKA
0.4493186 OKLAHOMA
k
5
4
3 ARIZONA
0.707914 KANSAS
5
4 ARKANSAS 0.4831379 NORTH DAKOTA
6
5 CALIFORNIA 0.7277162 INDIANA
Random Sample
Sample Name
7
6 COLORADO 0.5865002 MISSISSIPPI
8
7:ONNECTICU 0.7640596 ILLINOIS
9
8 DELAWARE 0.5783029 MISSOURI
525
10
15
INDIANA
MARYLAND
COLORADO
Suppose the Internal Revenue Service reported that the mean tax refund for the year 2022 was $3401. Assume the standard deviation is $82.5 and that the amounts refunded follow a normal probability distribution. Solve the following three parts? (For the answer to question 14, 15, and 16, start with making a bell curve. Identify on the bell curve where is mean, X, and area(s) to be determined.
1.What percent of the refunds are more than $3,500?
2. What percent of the refunds are more than $3500 but less than $3579?
3. What percent of the refunds are more than $3325 but less than $3579?
Chapter 16 Solutions
Applied Statistics in Business and Economics
Ch. 16.2 - Prob. 1SECh. 16.2 - Prob. 2SECh. 16.2 - Prob. 3SECh. 16.2 - Prob. 4SECh. 16.3 - A sample of 28 student scores on the chemistry...Ch. 16.3 - Prob. 6SECh. 16.4 - Prob. 7SECh. 16.4 - Prob. 8SECh. 16.5 - Prob. 9SECh. 16.5 - The results shown below are mean productivity...
Ch. 16.6 - Consumers are asked to rate the attractiveness of...Ch. 16.6 - Prob. 12SECh. 16.7 - Prob. 13SECh. 16.7 - Prob. 14SECh. 16 - Prob. 1CRCh. 16 - Prob. 2CRCh. 16 - Prob. 3CRCh. 16 - Prob. 4CRCh. 16 - Prob. 5CRCh. 16 - Prob. 6CRCh. 16 - Prob. 7CRCh. 16 - Prob. 8CRCh. 16 - Prob. 9CRCh. 16 - Prob. 10CRCh. 16 - (a) Why is a significant correlation not proof of...Ch. 16 - Prob. 15CECh. 16 - Prob. 16CECh. 16 - Prob. 17CECh. 16 - Prob. 18CECh. 16 - Prob. 19CECh. 16 - Instructions: In all exercises, you may use a...Ch. 16 - Prob. 21CECh. 16 - Prob. 22CECh. 16 - Prob. 23CECh. 16 - Prob. 24CECh. 16 - Prob. 25CECh. 16 - Instructions: In all exercises, you may use a...Ch. 16 - Prob. 27CECh. 16 - Instructions: In all exercises, you may use a...Ch. 16 - Prob. 29CECh. 16 - Prob. 30CECh. 16 - Prob. 31CECh. 16 - Prob. 32CECh. 16 - Prob. 33CECh. 16 - Prob. 34CECh. 16 - Instructions: In all exercises, you may use a...Ch. 16 - Prob. 36CECh. 16 - Prob. 37CE
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