Skip to main content

Science Chemistry Chemistry: An Atoms-Focused Approach

If the concentration of F e + 3 a q ions is the same in the listed acid solutions. Solution: The concentration of F e + 3 a q is not the same in all the four solutions. Explanation: When F e C l 3 is dissolved in the given samples, the F e + 3 ion forms a hydrated metal complex H 2 O 6 + 3 . The hydrated F e + 3 cation draws electron density away from the water molecules of its inner coordination sphere, which makes it possible for one or more of these molecules to donate an H + ion to water molecules outside the sphere. The hydrated F e + 3 ion is left with fewer H 2 O ligands and a bond between the complex ion and the O H - . The following equilibrium exists in the solution: F e H 2 O 6 + 3 a q + H 2 O l ⇌ F e H 2 O 5 O H + 2 a q + H 3 O + ( a q ) If an acid is added to this solution, the acid will increase the concentration of H 3 O + ions. This will cause the reaction equilibrium to shift to the left side, and the dissociation of F e H 2 O 6 + 3 will be supressed. Thus, depending on the concentration of H 3 O + ions added, the concentration of F e H 2 O 6 + 3 ions will change. The given acids are 1 M H N O 3 , 1 M H N O 2 , 1 M H 2 S O 3 , and 1 M C H 3 C O O H . Out of this, H N O 3 is a strong acid, and H N O 2 , H 2 S O 3 and C H 3 C O O H are weak acids. The dissociation of each acid is different due to different K a values, and hence, the concentration of H 3 O + ions added by 1 M of each acid will be different. Thus, the concentration of F e + 3 a q ions will be different in all the four solutions. Conclusion: The concentration of H 3 O + ions added by each given acid solution is different. Hence, in each solution, the equilibrium shifts to the left side, and the extent of the shift is different for each solution.

If the concentration of F e + 3 a q ions is the same in the listed acid solutions. Solution: The concentration of F e + 3 a q is not the same in all the four solutions. Explanation: When F e C l 3 is dissolved in the given samples, the F e + 3 ion forms a hydrated metal complex H 2 O 6 + 3 . The hydrated F e + 3 cation draws electron density away from the water molecules of its inner coordination sphere, which makes it possible for one or more of these molecules to donate an H + ion to water molecules outside the sphere. The hydrated F e + 3 ion is left with fewer H 2 O ligands and a bond between the complex ion and the O H - . The following equilibrium exists in the solution: F e H 2 O 6 + 3 a q + H 2 O l ⇌ F e H 2 O 5 O H + 2 a q + H 3 O + ( a q ) If an acid is added to this solution, the acid will increase the concentration of H 3 O + ions. This will cause the reaction equilibrium to shift to the left side, and the dissociation of F e H 2 O 6 + 3 will be supressed. Thus, depending on the concentration of H 3 O + ions added, the concentration of F e H 2 O 6 + 3 ions will change. The given acids are 1 M H N O 3 , 1 M H N O 2 , 1 M H 2 S O 3 , and 1 M C H 3 C O O H . Out of this, H N O 3 is a strong acid, and H N O 2 , H 2 S O 3 and C H 3 C O O H are weak acids. The dissociation of each acid is different due to different K a values, and hence, the concentration of H 3 O + ions added by 1 M of each acid will be different. Thus, the concentration of F e + 3 a q ions will be different in all the four solutions. Conclusion: The concentration of H 3 O + ions added by each given acid solution is different. Hence, in each solution, the equilibrium shifts to the left side, and the extent of the shift is different for each solution.

Solution Summary: The author explains that when FeCl_3 is dissolved in the given samples, the Fe+3 ion forms a hydrated metal complex (

Chemistry: An Atoms-Focused Approach

Chemistry: An Atoms-Focused Approach

14th Edition

ISBN: 9780393600681

Author: Gilbert

Publisher: W. W. Norton & Company

See similar textbooks

Concept explainers

Electrolysis is defined as the process of breaking down ionic compounds into their constituent elements by passing a direct electric current through the compound in a fluid state. The cathode reduces cations, while the anode oxidizes anions. An electroly…

Videos

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

Blurred answer

Chapter 16, Problem 16.85QA

Chapter 16, Problem 16.87QA

Students have asked these similar questions

Consider a solution of 0.00304 moles of 4-nitrobenzoic acid (pKa = 3.442) dissolved in 25 mL water and titrated with 0.0991 M NaOH. Calculate the pH at the equivalence point

What is the name of the following compound? SiMe3

K Draw the starting structure that would lead to the major product shown under the provided conditions. Drawing 1. NaNH2 2. PhCH2Br 4 57°F Sunny Q Search

Chapter 16 Solutions

Chemistry: An Atoms-Focused Approach

Ch. 16 - Prob. 16.2VP Ch. 16 - Prob. 16.3VP Ch. 16 - Prob. 16.4VP Ch. 16 - Prob. 16.5VP Ch. 16 - Prob. 16.6VP Ch. 16 - Prob. 16.7VP Ch. 16 - Prob. 16.8VP Ch. 16 - Prob. 16.9VP Ch. 16 - Prob. 16.10VP Ch. 16 - Prob. 16.11QA

Ch. 16 - Prob. 16.12QA Ch. 16 - Prob. 16.13QA Ch. 16 - Prob. 16.14QA Ch. 16 - Prob. 16.16QA Ch. 16 - Prob. 16.17QA Ch. 16 - Prob. 16.18QA Ch. 16 - Prob. 16.19QA Ch. 16 - Prob. 16.20QA Ch. 16 - Prob. 16.21QA Ch. 16 - Prob. 16.22QA Ch. 16 - Prob. 16.23QA Ch. 16 - Prob. 16.24QA Ch. 16 - Prob. 16.25QA Ch. 16 - Prob. 16.26QA Ch. 16 - Prob. 16.27QA Ch. 16 - Prob. 16.28QA Ch. 16 - Prob. 16.29QA Ch. 16 - Prob. 16.30QA Ch. 16 - Prob. 16.31QA Ch. 16 - Prob. 16.32QA Ch. 16 - Prob. 16.33QA Ch. 16 - Prob. 16.34QA Ch. 16 - Prob. 16.35QA Ch. 16 - Prob. 16.36QA Ch. 16 - Prob. 16.37QA Ch. 16 - Prob. 16.38QA Ch. 16 - Prob. 16.39QA Ch. 16 - Prob. 16.40QA Ch. 16 - Prob. 16.41QA Ch. 16 - Prob. 16.42QA Ch. 16 - Prob. 16.43QA Ch. 16 - Prob. 16.44QA Ch. 16 - Prob. 16.45QA Ch. 16 - Prob. 16.46QA Ch. 16 - Prob. 16.47QA Ch. 16 - Prob. 16.48QA Ch. 16 - Prob. 16.49QA Ch. 16 - Prob. 16.50QA Ch. 16 - Prob. 16.51QA Ch. 16 - Prob. 16.52QA Ch. 16 - Prob. 16.53QA Ch. 16 - Prob. 16.54QA Ch. 16 - Prob. 16.55QA Ch. 16 - Prob. 16.56QA Ch. 16 - Prob. 16.57QA Ch. 16 - Prob. 16.58QA Ch. 16 - Prob. 16.59QA Ch. 16 - Prob. 16.60QA Ch. 16 - Prob. 16.61QA Ch. 16 - Prob. 16.62QA Ch. 16 - Prob. 16.63QA Ch. 16 - Prob. 16.64QA Ch. 16 - Prob. 16.65QA Ch. 16 - Prob. 16.66QA Ch. 16 - Prob. 16.67QA Ch. 16 - Prob. 16.68QA Ch. 16 - Prob. 16.69QA Ch. 16 - Prob. 16.70QA Ch. 16 - Prob. 16.71QA Ch. 16 - Prob. 16.72QA Ch. 16 - Prob. 16.73QA Ch. 16 - Prob. 16.74QA Ch. 16 - Prob. 16.75QA Ch. 16 - Prob. 16.76QA Ch. 16 - Prob. 16.77QA Ch. 16 - Prob. 16.78QA Ch. 16 - Prob. 16.79QA Ch. 16 - Prob. 16.80QA Ch. 16 - Prob. 16.81QA Ch. 16 - Prob. 16.82QA Ch. 16 - Prob. 16.83QA Ch. 16 - Prob. 16.84QA Ch. 16 - Prob. 16.85QA Ch. 16 - Prob. 16.86QA Ch. 16 - Prob. 16.87QA Ch. 16 - Prob. 16.88QA Ch. 16 - Prob. 16.89QA Ch. 16 - Prob. 16.90QA Ch. 16 - Prob. 16.91QA Ch. 16 - Prob. 16.92QA Ch. 16 - Prob. 16.93QA Ch. 16 - Prob. 16.94QA Ch. 16 - Prob. 16.95QA Ch. 16 - Prob. 16.96QA Ch. 16 - Prob. 16.97QA Ch. 16 - Prob. 16.98QA Ch. 16 - Prob. 16.99QA

Knowledge Booster

Background pattern image

Chemistry

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.

Similar questions

SEE MORE QUESTIONS

Recommended textbooks for you

Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry for Engineering Students
Chemistry
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Cengage Learning
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemistry
Chemistry
ISBN:9781133611097
Author:Steven S. Zumdahl
Publisher:Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning

Text book image

Chemistry & Chemical Reactivity

Chemistry

ISBN:9781337399074

Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel

Publisher:Cengage Learning

Text book image

Chemistry for Engineering Students

Chemistry

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Cengage Learning

Text book image

Chemistry: Principles and Reactions

Chemistry

ISBN:9781305079373

Author:William L. Masterton, Cecile N. Hurley

Publisher:Cengage Learning

Text book image

Chemistry

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Cengage Learning

Text book image

Chemistry

ISBN:9781133611097

Author:Steven S. Zumdahl

Publisher:Cengage Learning

Text book image

Chemistry: The Molecular Science

Chemistry

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:Cengage Learning

SEE MORE TEXTBOOKS

Electrolysis; Author: Tyler DeWitt;https://www.youtube.com/watch?v=dRtSjJCKkIo;License: Standard YouTube License, CC-BY