Chapter 16, Problem 16.64QP

Interpretation Introduction

Interpretation: The $\text{pH}$ of a $0.150\text{M}$ solution of sulphorous acid is to be calculated.

Concept introduction: The $\text{pH}$ of any compound is the log of the concentration of hydronium ions released by that compound upon dissociation.

The $\text{pH}$ is calculated by the formula,

$\text{pH}=-\log \left[{\text{H}}^{+}\right]$

To determine: The $\text{pH}$ of a $0.150\text{M}$ solution of ${\text{H}}_2{\text{SO}}_3$.