Chapter 16, Problem 16.108QP

Interpretation Introduction

Interpretation: The volume of $\text{6}\text{.0}\text{M}\text{NaOH}$ that must be added to $\text{0}\text{.500}\text{L}$ of a buffer that is $\text{0}\text{.0200}\text{M}$ acetic acid and $\text{0}\text{.0250}\text{M}$ sodium acetate to raise the $\text{pH}$ to $5.75$ at ${\text{25}}^{\text{o}}\text{C}$ is to be calculated.

Concept introduction: The $\text{pH}$ of the solution is calculated by Henderson-Hasselbalch equation,

$\text{pH}=\text{p}{K}_{\text{a}}+\text{log}\frac{\left[\text{Base}\right]}{\left[\text{Acid}\right]}$

The molarity of the solution is calculated by the formula,

$\text{Molarity}=\frac{\text{Amount}\text{of}\text{solute}\left(\text{in}\text{moles}\right)}{\text{Volume}}$

To determine: The volume of $\text{6}\text{.0}\text{M}\text{NaOH}$ that must be added to $\text{0}\text{.500}\text{L}$ of a buffer that is $\text{0}\text{.0200}\text{M}$ acetic acid and $\text{0}\text{.0250}\text{M}$ sodium acetate to raise the $\text{pH}$ to $5.75$ at ${\text{25}}^{\text{o}}\text{C}$.