The total vapor pressure at 81 ∘ C over benzene – toluene solution with χ b e n z = 0.250 has to be calculated. Concept Introduction: According to Raoult’s law, in an ideal solution of two volatile liquids, the total vapor pressure of the solution is the sum of individual vapor pressure. P t o t a l = P A + P B .... ( 1 ) Where, P A = χ A P A ∘ a n d P B = χ B P B ∘ . The equation ( 1 ) can be further modified. P t o t a l = P A + P B P t o t a l = χ A P A ∘ + χ B P B ∘ P t o t a l = χ A P A ∘ + ( 1 − χ A ) P B ∘ [ ∵ χ A + χ B = 1 ] P t o t a l = P B ∘ + χ A ( P A ∘ − P B ∘ )

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Answer 1

Question

Chapter 16, Problem 16.53P

(a)

Interpretation Introduction

Interpretation:

The total vapor pressure at 81∘C over benzene – toluene solution with χbenz=0.250 has to be calculated.

Concept Introduction:

According to Raoult’s law, in an ideal solution of two volatile liquids, the total vapor pressure of the solution is the sum of individual vapor pressure.

Ptotal=PA+PB ....(1)

Where, PA=χAPA∘ and PB=χBPB∘ .

The equation (1) can be further modified.

Ptotal=PA+PBPtotal=χAPA∘+χBPB∘Ptotal=χAPA∘+(1−χA)PB∘ [∵ χA+χB=1]Ptotal=PB∘ +χA(PA∘−PB∘ )

(b)

Interpretation Introduction

Interpretation:

The mole fraction of benzene in the vapor phases over the solution has to be calculated.

Concept Introduction:

Refer to part (a).

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Answer 2

Question

Chapter 16, Problem 16.53P

(a)

Interpretation Introduction

Interpretation:

The total vapor pressure at 81∘C over benzene – toluene solution with χbenz=0.250 has to be calculated.

Concept Introduction:

According to Raoult’s law, in an ideal solution of two volatile liquids, the total vapor pressure of the solution is the sum of individual vapor pressure.

Ptotal=PA+PB ....(1)

Where, PA=χAPA∘ and PB=χBPB∘ .

The equation (1) can be further modified.

Ptotal=PA+PBPtotal=χAPA∘+χBPB∘Ptotal=χAPA∘+(1−χA)PB∘ [∵ χA+χB=1]Ptotal=PB∘ +χA(PA∘−PB∘ )

(b)

Interpretation Introduction

Interpretation:

The mole fraction of benzene in the vapor phases over the solution has to be calculated.

Concept Introduction:

Refer to part (a).

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Answer 3

Question

Chapter 16, Problem 16.53P

(a)

Interpretation Introduction

Interpretation:

The total vapor pressure at 81∘C over benzene – toluene solution with χbenz=0.250 has to be calculated.

Concept Introduction:

According to Raoult’s law, in an ideal solution of two volatile liquids, the total vapor pressure of the solution is the sum of individual vapor pressure.

Ptotal=PA+PB ....(1)

Where, PA=χAPA∘ and PB=χBPB∘ .

The equation (1) can be further modified.

Ptotal=PA+PBPtotal=χAPA∘+χBPB∘Ptotal=χAPA∘+(1−χA)PB∘ [∵ χA+χB=1]Ptotal=PB∘ +χA(PA∘−PB∘ )

(b)

Interpretation Introduction

Interpretation:

The mole fraction of benzene in the vapor phases over the solution has to be calculated.

Concept Introduction:

Refer to part (a).

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 16, Problem 16.53P

(a)

Interpretation Introduction

Interpretation:

The total vapor pressure at 81∘C over benzene – toluene solution with χbenz=0.250 has to be calculated.

Concept Introduction:

According to Raoult’s law, in an ideal solution of two volatile liquids, the total vapor pressure of the solution is the sum of individual vapor pressure.

Ptotal=PA+PB ....(1)

Where, PA=χAPA∘ and PB=χBPB∘ .

The equation (1) can be further modified.

Ptotal=PA+PBPtotal=χAPA∘+χBPB∘Ptotal=χAPA∘+(1−χA)PB∘ [∵ χA+χB=1]Ptotal=PB∘ +χA(PA∘−PB∘ )

(b)

Interpretation Introduction

Interpretation:

The mole fraction of benzene in the vapor phases over the solution has to be calculated.

Concept Introduction:

Refer to part (a).

Expert Solution & Answer

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Check out a sample textbook solution

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Answer 5

Chapter 16, Problem 16.53P

(a)

Interpretation Introduction

Interpretation:

The total vapor pressure at 81∘C over benzene – toluene solution with χbenz=0.250 has to be calculated.

Concept Introduction:

According to Raoult’s law, in an ideal solution of two volatile liquids, the total vapor pressure of the solution is the sum of individual vapor pressure.

Ptotal=PA+PB ....(1)

Where, PA=χAPA∘ and PB=χBPB∘ .

The equation (1) can be further modified.

Ptotal=PA+PBPtotal=χAPA∘+χBPB∘Ptotal=χAPA∘+(1−χA)PB∘ [∵ χA+χB=1]Ptotal=PB∘ +χA(PA∘−PB∘ )

(b)

Interpretation Introduction

Interpretation:

The mole fraction of benzene in the vapor phases over the solution has to be calculated.

Concept Introduction:

Refer to part (a).

Answer 6

Chapter 16, Problem 16.53P

(a)

Interpretation Introduction

Interpretation:

The total vapor pressure at 81∘C over benzene – toluene solution with χbenz=0.250 has to be calculated.

Concept Introduction:

According to Raoult’s law, in an ideal solution of two volatile liquids, the total vapor pressure of the solution is the sum of individual vapor pressure.

Ptotal=PA+PB ....(1)

Where, PA=χAPA∘ and PB=χBPB∘ .

The equation (1) can be further modified.

Ptotal=PA+PBPtotal=χAPA∘+χBPB∘Ptotal=χAPA∘+(1−χA)PB∘ [∵ χA+χB=1]Ptotal=PB∘ +χA(PA∘−PB∘ )

Answer 7

Chapter 16, Problem 16.53P

(a)

Interpretation Introduction

Interpretation:

The total vapor pressure at 81∘C over benzene – toluene solution with χbenz=0.250 has to be calculated.

Concept Introduction:

According to Raoult’s law, in an ideal solution of two volatile liquids, the total vapor pressure of the solution is the sum of individual vapor pressure.

Ptotal=PA+PB ....(1)

Where, PA=χAPA∘ and PB=χBPB∘ .

The equation (1) can be further modified.

Ptotal=PA+PBPtotal=χAPA∘+χBPB∘Ptotal=χAPA∘+(1−χA)PB∘ [∵ χA+χB=1]Ptotal=PB∘ +χA(PA∘−PB∘ )

Answer 8

(b)

Interpretation Introduction

Interpretation:

The mole fraction of benzene in the vapor phases over the solution has to be calculated.

Concept Introduction:

Refer to part (a).

Answer 9

(b)

Interpretation Introduction

Interpretation:

The mole fraction of benzene in the vapor phases over the solution has to be calculated.

Concept Introduction:

Refer to part (a).

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

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Answer 13

Ch. 16 - Prob. 16.1P Ch. 16 - Prob. 16.2P Ch. 16 - Prob. 16.3P Ch. 16 - Prob. 16.4P Ch. 16 - Prob. 16.5P Ch. 16 - Prob. 16.6P Ch. 16 - Prob. 16.7P Ch. 16 - Prob. 16.8P Ch. 16 - Prob. 16.9P Ch. 16 - Prob. 16.10P

Concept explainers

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Interpretation:

The mole fraction of benzene in the vapor phases over the solution has to be calculated.

Concept Introduction:

Refer to part (a).

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Chapter 16 Solutions

Concept explainers

Videos

Interpretation: The mole fraction of benzene in the vapor phases over the solution has to be calculated. Concept Introduction: Refer to part (a).

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Chapter 16 Solutions

Interpretation:

The mole fraction of benzene in the vapor phases over the solution has to be calculated.

Concept Introduction:

Refer to part (a).