The reason as to why the bond dissociation energy for the C − C bond in ethane is much higher than the bond dissociation energy for the labeled C − C bond in but − 1 − ene is to be explained. Concept introduction: In organic chemistry , the formation of carbocation or carbanion or radical occurs due to the heterolysis or homolysis process Heterolysis is the process in which unequal sharing of electrons results in the breaking of the bond, whereas homolysis is the process in which equal sharing of electrons results in the breaking of the bond.

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Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 16, Problem 16.36P

Interpretation Introduction

Interpretation: The reason as to why the bond dissociation energy for the C−C bond in ethane is much higher than the bond dissociation energy for the labeled C−C bond in but−1−ene is to be explained.

Concept introduction: In organic chemistry, the formation of carbocation or carbanion or radical occurs due to the heterolysis or homolysis process Heterolysis is the process in which unequal sharing of electrons results in the breaking of the bond, whereas homolysis is the process in which equal sharing of electrons results in the breaking of the bond.

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The complex anion in Ba₂[Cr(CN)6] is a tetragonally distorted octahedral complex (Dan). Baz[Cr(CN)6] is paramagnetic at room temperature with S = 1. Assume that the complex is a low-spin complex. a) Identify if the [Cr(CN)6] anionic complex has 4 long and 2 short bonds (left side of figure) or if the complex has 4 short and 2 long bonds (right side of figure) with respect to Oh symmetry. Use crystal field theory to answer this question. Explain/rationalize your decision. Can the provided information decide on the order of orbital energies? Dah Tetragonal Distortion ய Dab z-compression z-elongation x and y elongation O symmetry x and y compression E eg d² dx²-y² t2g dxy dxz dyz Question 4 a) continued: Provide your explanations in the space below. b) At low temperatures Ba₂[Cr(CN)6] is ferromagnetically ordered with a phase transition to a paramagnetic phase at Tc = 150K. Sketch the magnetic susceptibility vs. temperature in the diagram below. Indicate Tc as well as the paramagnetic and…

Answer 2

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Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 16, Problem 16.36P

Interpretation Introduction

Interpretation: The reason as to why the bond dissociation energy for the C−C bond in ethane is much higher than the bond dissociation energy for the labeled C−C bond in but−1−ene is to be explained.

Concept introduction: In organic chemistry, the formation of carbocation or carbanion or radical occurs due to the heterolysis or homolysis process Heterolysis is the process in which unequal sharing of electrons results in the breaking of the bond, whereas homolysis is the process in which equal sharing of electrons results in the breaking of the bond.

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Answer 3

Question

Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 16, Problem 16.36P

Interpretation Introduction

Interpretation: The reason as to why the bond dissociation energy for the C−C bond in ethane is much higher than the bond dissociation energy for the labeled C−C bond in but−1−ene is to be explained.

Concept introduction: In organic chemistry, the formation of carbocation or carbanion or radical occurs due to the heterolysis or homolysis process Heterolysis is the process in which unequal sharing of electrons results in the breaking of the bond, whereas homolysis is the process in which equal sharing of electrons results in the breaking of the bond.

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Answer 4

Question

Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 16, Problem 16.36P

Interpretation Introduction