Elementary Surveying (14th Edition)
Elementary Surveying (14th Edition)
14th Edition
ISBN: 9780133758887
Author: Charles D. Ghilani, Paul R. Wolf
Publisher: PEARSON
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Chapter 16, Problem 16.21P
To determine

To adjust:

The baselines.

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The given beam has continuous lateral support. If the live load is twice the dead load, what is the maximum total service load, in kips / ft, that can be supported? A992 steel is used: Fy = 50 ksi, Fu=65 ksi. Take L = 30 ft. bf For W40 x 149: 2tf = 7.11, = = 54.3, Z 598 in.³ tw W W40 X 149 L (Express your answers to three significant figures.) a. Use LRFD. Wtotal = kips/ft b. Use ASD. Wtotal kips/ft
The beam shown in the figure below is a W16 × 31 of A992 steel and has continuous lateral support. The two concentrated loads are service live loads. Neglect the weight of the beam and determine whether the beam is adequate. Suppose that P = 52 k. For W16 × 31: d = 15.9 in., tw = 0.275 in., h/tw = 51.6, and M = M₁ = 203 ft-kip, Mn/₁ = Mp/α = 135 ft-kip. P Р W16 x 31 a. Use LRFD. Calculate the required moment strength, the allowable shear strength, and the maximum shear. (Express your answers to three significant figures.) Mu = OvVn = ft-kip kips kips Vu = Beam is -Select- b. Use ASD. Calculate the required moment strength, the allowable shear strength, and the maximum shear. (Express your answers to three significant figures.) Ma = Vn/b - Va = Beam is -Select- ft-kip kips kips
Determine the smallest value of yield stress Fy, for which a W-, M-, or S-shape from the list below will become slender. bf/2tfh/tw Shape W12 × 72 8.99 22.6 W12 × 26 8.54 47.2 M4 × 6 11.9 22.0 M12 x 11.8 6.81 62.5 M6 × 4.4 5.39 47.0 S24 × 80 4.02 41.4 S10 × 35 5.03 13.4 (Express your answer to three significant figures.) Fy = ksi To which shape does this value apply? -Select- ✓
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