Explanation Given data: A 20.27 gram sample of a metal carbonate (MCO 3 ) is combined with 500 mL of a 1.00 M HCl solution. The excess HCl acid is then neutralized by 32.80 mL of 0.588 M NaOH Finding of unknown metal (M) in the metal carbonate MCO 3 The balanced equations for the two given reactions are as follows, Combination of MCO 3 with HCl MCO 3(s) + 2 HCl → MCl 2 ( a q ) + CO 2 ( g ) + H 2 O ( l ) Neutralization of HCl with NaOH HCl ( a q ) + NaOH ( a q ) → NaCl ( a q ) + H 2 O ( l ) First, find the number of moles of excess acid from the reaction with NaOH 0.03280 L × 0.500 mol NaOH 1 L soln × 1 mol HCl 1 mol NaOH = 0

1st Edition

ISBN: 9781259383120

Author: Burdge

Publisher: McGraw Hill Custom

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Chapter 16, Problem 16.171QP

Interpretation Introduction

Interpretation:

The unknown metal in the given metal carbonate MCO3 has to be found

Concept Information:

Molarity:

Molarity can be defined as the ratio of number of moles of solute to the number of litres of solution. The concentration of solute in solution is measured using a concentration unit called molarity.

The unit of molarity is moles per litre.

The equation for molarity can be given as,

Molarity (M) = number of moles of solutelitres of solution

To Find: The unknown metal (M) in the given metal carbonate MCO3

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Chapter 16, Problem 16.170QP

Chapter 16, Problem 16.172QP

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Solution Summary: The author explains that the unknown metal in the given metal carbonate is Magnesium. The equation for molarity is the ratio of number of moles of solute to the amount of litres of solution.

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