Ribavirin contains a 1,2,4-triazole ring. Why the ring is aromatic is to be explained. Concept introduction: A compound to become aromatic should obey Huckel’s rule. According to Huckel’s rule, any species that is cyclic, planar and has (4n+2) delocalized Ï€ electrons will be aromatic and stable. Thus species with 2, 6, 10, 14 etc. Ï€ electrons will be aromatic and stable. To explain: Why the 1,2,4-triazole ring is aromatic.

Question

For each reaction below, decide if the first stable organic product that forms in solution will create a new CC bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. ? NH2 MgBr Will the first product that forms in this reaction create a new CC bond? ○ Yes ○ No MgBr ? Will the first product that forms in this reaction create a new CC bond? O Yes O No Click and drag to start drawing a structure. :☐ G x c olo Ar HE

Answer 1

Question

Chapter 15.SE, Problem 38AP

Interpretation Introduction

Interpretation:

Ribavirin contains a 1,2,4-triazole ring. Why the ring is aromatic is to be explained.

Concept introduction:

A compound to become aromatic should obey Huckel’s rule. According to Huckel’s rule, any species that is cyclic, planar and has (4n+2) delocalized Ï€ electrons will be aromatic and stable. Thus species with 2, 6, 10, 14 etc. Ï€ electrons will be aromatic and stable.

To explain:

Why the 1,2,4-triazole ring is aromatic.

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For each reaction below, decide if the first stable organic product that forms in solution will create a new CC bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. ? NH2 MgBr Will the first product that forms in this reaction create a new CC bond? ○ Yes ○ No MgBr ? Will the first product that forms in this reaction create a new CC bond? O Yes O No Click and drag to start drawing a structure. :☐ G x c olo Ar HE

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