Use the Divergence Theorem to find the flux of F across the surface σ with outward orientation. F x , y , z = x 2 y i − x y 2 j + z + 2 k ; σ is the surface of the solid bounded above by the plane z = 2 x and below by the paraboloid z = x 2 + y 2 .
Use the Divergence Theorem to find the flux of F across the surface σ with outward orientation. F x , y , z = x 2 y i − x y 2 j + z + 2 k ; σ is the surface of the solid bounded above by the plane z = 2 x and below by the paraboloid z = x 2 + y 2 .
Use the Divergence Theorem to find the flux of F across the surface
σ
with outward orientation.
F
x
,
y
,
z
=
x
2
y
i
−
x
y
2
j
+
z
+
2
k
;
σ
is the surface of the solid bounded above by the plane
z
=
2
x
and below by the paraboloid
z
=
x
2
+
y
2
.
Determine the flux of F(x, y, z) = < −x2 + x, y, 8x3 − z + 9 > across the surface with an upward orientation. Let the surface be the portion of the paraboloid z = 9 − 4x2 −4y2 on the first octant above the plane z = 1.
Determine the flux of F(x, y, z) = < −x2 + x, y, 8x3 − z + 9 > across the surface with an upward orientation. Let the surface be the portion of the paraboloid z = 9 − 4x2 −4y2 on the first octant above the plane z = 1. (note: do not use gauss' theorem)
Let the surface xz – yz³ + yz?
=
2, then
-
the equation of the tangent plane to the
surface at the point (2, –1, 1) is:
O x – y + 3z = 5
O x - 3z = 5
O x + 3z = 5
O x + y+ 3z = 5
O y+ 3z = 5
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