Set up, but do not evaluate, an iterated integral equal to the given surface integral by projecting σ on (a) the x y -plane , (b) the x z -plane , and (c) the x z -plane . ∬ σ x y z d S , where σ is the portion of the plane 2 x + 3 y + 4 z = 12 in the first octant.
Set up, but do not evaluate, an iterated integral equal to the given surface integral by projecting σ on (a) the x y -plane , (b) the x z -plane , and (c) the x z -plane . ∬ σ x y z d S , where σ is the portion of the plane 2 x + 3 y + 4 z = 12 in the first octant.
Set up, but do not evaluate, an iterated integral equal to the given surface integral by projecting
σ
on (a) the
x
y
-plane
,
(b) the
x
z
-plane
,
and (c) the
x
z
-plane
.
∬
σ
x
y
z
d
S
,
where
σ
is the portion of the plane
2
x
+
3
y
+
4
z
=
12
in the first octant.
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
could you please show the computation of this by wires
4 Consider f(x) periodic function with period 2, coinciding with (x) = -x on the interval
[,0) and being the null function on the interval [0,7). The Fourier series of f:
(A) does not converge in quadratic norm to f(x) on [−π,π]
(B) is pointwise convergent to f(x) for every x = R
П
(C) is in the form
-
4
∞
+Σ ak cos(kx) + bk sin(kx), ak ‡0, bk ‡0
k=1
(D) is in the form ak cos(kx) + bk sin(kx), ak 0, bk 0
k=1
Solve the equation.
Chapter 15 Solutions
Calculus Early Transcendentals, Binder Ready Version
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