Explanation Show the free diagram of the cranberry and barrier. Write the expression of the gravitational potential energy. GPE= V 1 = m g h (I) Here, mass of the crate is m , acceleration due to gravity is g and the height above the ground is h . Write the expression of the conservation of energy. T 1 + V 1 = T 2 + V 2 T 1 + V 1 = 1 2 m C ( v C ) 1 2 + V 2 (II) Determine the conservation of momentum of cranberry with respect x’ -axis direction. m C ( v C x ′ ) 1 = m C ( v C x ′ ) 2 (III) Write the formula for coefficient of restitution ( e ) along y ′ − a x i s . e = ( v P ) 2 − ( v C y ′ ) 2 ( v C y ′ ) 1 − ( v P ) 1 (IV) Here, the velocity of the dinner plate is ( v P ) , the velocity of the cranberry is ( v C y ′ ) Write the formula for velocity of the cranberry along y − a x i s . v y = ( v 0 ) y + a C t (V) Here, the final velocity of the cranberry along y − a x i s is v y , the initial velocity of the cranberry along y − a x i s is ( v 0 ) y , the acceleration due to gravity of cranberry is a C , and the time is t . Write the formula for position of the cranberry along y − a x i s . s y = ( s 0 ) y + ( v 0 ) y t + 1 2 ( a C ) y t 2 (VI) Here, the final position of the cranberry along y − a x i s is s y , the initial position of the cranberry along y − a x i s is ( s 0 ) y , the initial velocity of the cranberry along y − a x i s is ( v o ) y , the acceleration due to gravity is ( a C ) y , and the time is t . Write the formula for velocity of the cranberry along x − a x i s . s x = ( s 0 ) x + v x t (VII) Here, the horizontal velocity of the cranberry along x − a x i s is v x , the initial velocity of the cranberry along x − a x i s is ( s 0 ) x , the acceleration due to gravity of cranberry is v x , and the time is t . Determine the height of the barrier. h = s y + sin θ d (VIII) Conclusion: Refer Figure (1). The weight of cranberry is W = m g Substitute 1.75 m for h , W for m g in Equation (I). V 1 = W ( 3.5 ) = 3.5 W Substitute 0 for T 1 , 3.5 W for V 1 , and ( W 32.2 ) for m C in Equation (III). 0 + 3.5 W = 1 2 ( W 32.2 ) ( v C ) 1 2 + 0 ( v C ) 1 = 15.01 ft/s (VIII) Substitute ( 15.01 ) sin θ for ( v C x ′ ) 1 , and ( v C ) 2 cos ϕ for ( v C x ′ ) 2 in Equation (IV) m C ( 15

Engineering Mechanics: Statics & Dynamics (14th Edition)

14th Edition

ISBN: 9780133915426

Author: Russell C. Hibbeler

Publisher: PEARSON

See similar textbooks

Concept explainers

Forming and Shaping

Metal forming is a category of metalworking process through which the material can be given the desired shape and size by subjecting it to plastic deformation, where the component undergoes bulk deformation process upon application of loads. Unlike the s…

Videos

Question

Chapter 15.4, Problem 90P

To determine

The dimension of the barrier, d .

The height of the barrier, h .

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 15.4, Problem 89P

Chapter 15.4, Problem 91P

Students have asked these similar questions

Water enters an adiabatic nozzle steadily at 500 kPa and 300˚C with a mass flow rate of 6000 kg/h and leaves at 100 kPa and 45 m/s. The inlet area of the nozzle is 40 cm2. Take the Cp of CO2 to be 4.2 kJ/kgK and the specific volume of water to 0.001 m3/kg. Determine the inlet velocity and the exit temperature.

Water enters the constant 130 mm inside-diameter tubes of a boiler at 7 MPa and 65˚C and leaves the tubes at 6 MPa and 450˚C with a velocity of 80 m/s. Calculate the velocity of the water at the tube inlet and the inlet volume flow rate. Hint: the mass flow rate remains constant.

Q1: A. One of the researchers discovered a patent related to the development of a certain software module in mobile devices, and when he emailed one of the companies producing these devices, they asked him to send the research to try it on their devices, and after a while this researcher discovered that his discovery was used by this company without referring to him or buying this discovery, What do you think about the above. B. As a quality control engineer in one of the electrical appliance factories, I discovered that the technical worker responsible for inspecting one of these products seals its validity without inspecting it. when I filed a complaint with the administration, the administration neglected the complaint, arguing that there was no time to inspect it again due to lack of time to prepare the consumer. 1. What are the consequences of this action, it is possible that there is a bad in the product due to lack of examination. 2. The actions that you should take because of…

Chapter 15 Solutions

Engineering Mechanics: Statics & Dynamics (14th Edition)

Ch. 15.2 - Determine the impulse of the force for t = 2 s.Ch. 15.2 - The 0.5kg ball strikes the rough ground and...Ch. 15.2 - Prob. 2FP Ch. 15.2 - Prob. 3FP Ch. 15.2 - The wheels of the 1.5-Mg car generate the traction...Ch. 15.2 - Prob. 5FP Ch. 15.2 - A man kicks the 150-g ball such that it leaves the...Ch. 15.2 - If the coefficient of kinetic friction between the...Ch. 15.2 - Prob. 3P Ch. 15.2 - Each of the cables can sustain a maximum tension...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

The dimension of the barrier, d . The height of the barrier, h .

Solution Summary: The author shows the free diagram of the cranberry and barrier. Write the expression of gravitational potential energy.