Chapter 15.2, Problem 8PP

To determine

The amount of water in grams that react.

Answer to Problem 8PP

  $36\text{ g}$

Explanation of Solution

Given:

  $64.\text{1 g}$ of sulfur dioxide which is 1 mole.

  $159.9\text{ g}$ of bromine which is 1 mole.

  $161.\text{9 g}$ of hydrogen bromide which is 2 moles.

  $91.8\text{ g}$ of sulfuric acid which is its mole.

Formula used:

  ${\text{SO}}_{\text{2}}\text{+}{\text{Br}}_{\text{2}}\text{+}{\text{2H}}_{\text{2}}\text{O}\text{=}\text{2HBr}\text{+}{\text{H}}_{\text{2}}{\text{SO}}_{\text{4}}$

Calculation:

Moles of sulfur dioxide is 1.

Moles of bromine is 1.

So, 1 mole sulfur dioxide reacts with one mole bromine and 2 moles of water to give 2 mole hydrogen bromide and 1 mole sulfuric acid.

So, 2 moles water weights $36\text{ g}$ .

Conclusion:

The amount of water react is $36\text{ g}$ .