Chapter 15.2, Problem 1PPB

Write the equation for the equilibrium that corresponds to each of the following reaction quotients.

$\begin{array}{l}\left(\text{a}\right)Q_c=\frac{{\left[\text{HCl}\right]}^2}{\left[{\text{H}}_{\text{2}}\right]\left[{\text{Cl}}_{\text{2}}\right]}\\ \left(\text{b}\right)Q_c=\frac{\left[\text{HF}\right]}{\left[{\text{H}}^{\text{+}}\right]\left[{\text{F}}^{\text{-}}\right]}\\ \left(\text{c}\right)Q_c=\frac{\left[\text{Cr}{\left(\text{OH}\right)}_4^{-}\right]}{\left[{\text{Cr}}^{\text{+}}\right]{\left[{\text{OH}}^{\text{-}}\right]}^4}\\ \left(\text{d}\right)Q_c=\frac{\left[{\text{H}}^{+}\right]\left[{\text{ClO}}^{\text{-}}\right]}{\left[\text{HClO}\right]}\\ \left(\text{e}\right)Qc=\frac{\left[{\text{H}}^{\text{+}}\right]\left[{\text{HSO}}_{\text{3}}^{\text{-}}\right]}{\left[{\text{H}}_{\text{2}}{\text{SO}}_{\text{3}}\right]}\\ \left(\text{f}\right)Q_c=\frac{{\left[\text{NOBr}\right]}^2}{{\left[\text{NO}\right]}^2\left[{\text{Br}}_{\text{2}}\right]}\end{array}$