Big Java Late Objects
2nd Edition
ISBN: 9781119330455
Author: Horstmann
Publisher: WILEY
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Question
Chapter 15, Problem 9PE
Program Plan Intro
Break digits
Program plan:
Main.java
- Create a class named “Main”. Inside the class,
- Define the “main ()” method.
- Prompt the user to enter the digit.
- Define the scanner input.
- Get input.
- Loop that iterates to split the values.
- Call the “IntegerSplitter()” method.
- Print the resultant value.
- Define the “main ()” method.
IntegerSplitter.java
- Create a class named “IntegerSplitter”. Inside the class,
- Define the “split ()” method.
- Create a new stack
- Loop that iterates to validate the numbers.
- Push the values
- Find the quotient.
- Condition to validate the values of the stack
- Display the values
- Loop that iterates for the size of the stack
- Display the values
- Define the “split ()” method.
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Exercise 1 Function and Structure [30 pts]
Please debug the following program and answer the following questions. There is a cycle in a linked
list if some node in the list can be reached again by continuously following the next pointer.
#include
typedef struct node {
int value;
struct node *next;
} node;
int 11_has_cycle (node *first)
if (first
==
node *head =
{
NULL) return 0;
first;
while (head->next != NULL) {
}
if (head
first) {
return 1; }
head = head->next;
return 0;
void test ll_has_cycle () {
int i;
node nodes [6];
for (i = 0; i < 6; i++) {
nodes [i] .next = NULL;
nodes [i].value = i;
}
nodes [0] .next
=
&nodes [1];
nodes [1] .next
=
&nodes [2];
nodes [2] .next
=
&nodes [3];
nodes [3] .next
nodes [4] .next
&nodes [4];
NULL;
nodes [5] .next = &nodes [0];
printf("1. Checking first list for cycles. \n Function 11_has_cycle says it
has s cycle\n\n", 11_has_cycle (&nodes [0])?"a":"no");
printf("2. Checking length-zero list for cycles. \n Function 11_has_cycle
says it has %s…
how to read log logs
Discrete Mathematics for Computer Engineering
Chapter 15 Solutions
Big Java Late Objects
Ch. 15.1 - Prob. 1SCCh. 15.1 - Prob. 2SCCh. 15.1 - Prob. 3SCCh. 15.1 - Prob. 4SCCh. 15.2 - Prob. 5SCCh. 15.2 - Prob. 6SCCh. 15.2 - Prob. 7SCCh. 15.2 - Prob. 8SCCh. 15.2 - Prob. 9SCCh. 15.3 - Prob. 10SC
Ch. 15.3 - Prob. 11SCCh. 15.3 - Prob. 12SCCh. 15.3 - Prob. 13SCCh. 15.3 - Prob. 14SCCh. 15.3 - Prob. 15SCCh. 15.4 - Prob. 16SCCh. 15.4 - Prob. 17SCCh. 15.4 - Prob. 18SCCh. 15.4 - Prob. 19SCCh. 15.4 - Prob. 20SCCh. 15.5 - Prob. 21SCCh. 15.5 - Prob. 22SCCh. 15.5 - Prob. 23SCCh. 15.5 - Prob. 24SCCh. 15.5 - Prob. 25SCCh. 15.6 - Prob. 26SCCh. 15.6 - Prob. 27SCCh. 15.6 - Prob. 28SCCh. 15.6 - Prob. 29SCCh. 15.6 - Prob. 30SCCh. 15 - Prob. 1RECh. 15 - Prob. 2RECh. 15 - Prob. 3RECh. 15 - Prob. 4RECh. 15 - Prob. 5RECh. 15 - Prob. 6RECh. 15 - Prob. 7RECh. 15 - Prob. 8RECh. 15 - Prob. 9RECh. 15 - Prob. 10RECh. 15 - Prob. 11RECh. 15 - Prob. 12RECh. 15 - Prob. 13RECh. 15 - Prob. 14RECh. 15 - Prob. 15RECh. 15 - Prob. 16RECh. 15 - Prob. 17RECh. 15 - Prob. 18RECh. 15 - Prob. 19RECh. 15 - Prob. 20RECh. 15 - Prob. 21RECh. 15 - Prob. 22RECh. 15 - Prob. 23RECh. 15 - Prob. 24RECh. 15 - Prob. 25RECh. 15 - Prob. 26RECh. 15 - Prob. 1PECh. 15 - Prob. 2PECh. 15 - Prob. 3PECh. 15 - Prob. 4PECh. 15 - Prob. 5PECh. 15 - Prob. 6PECh. 15 - Prob. 7PECh. 15 - Prob. 8PECh. 15 - Prob. 9PECh. 15 - Prob. 10PECh. 15 - Prob. 11PECh. 15 - Prob. 12PECh. 15 - Prob. 13PECh. 15 - Prob. 14PECh. 15 - Prob. 15PECh. 15 - Prob. 16PECh. 15 - Prob. 17PECh. 15 - Prob. 18PECh. 15 - Prob. 19PECh. 15 - Prob. 20PECh. 15 - Prob. 21PECh. 15 - Prob. 22PECh. 15 - Prob. 1PPCh. 15 - Prob. 2PPCh. 15 - Prob. 3PPCh. 15 - Prob. 4PPCh. 15 - Prob. 5PPCh. 15 - Prob. 6PPCh. 15 - Prob. 7PPCh. 15 - Prob. 8PPCh. 15 - Prob. 9PPCh. 15 - Prob. 10PPCh. 15 - Prob. 11PPCh. 15 - Prob. 12PPCh. 15 - Prob. 13PPCh. 15 - Prob. 14PP
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