Big Java Late Objects
Big Java Late Objects
2nd Edition
ISBN: 9781119330455
Author: Horstmann
Publisher: WILEY
Question
Book Icon
Chapter 15, Problem 21PE
Program Plan Intro

Maze

Program plan:

Maze.java

  • Create a class named “Maze”. Inside the class,
    • Declare the required variables
    • Define the “Maze ()” method.
      • Initialize the values.
    • Define the “pathsFrom ()” method.
      • Create an array list.
      • Use necessary conditions to validate the rows and columns.
      • Return the path required after validation.
      • Loop that iterates for the path
      • Call the method “extend()”
    • Define the “extend ()” method.
      • Assign the value
      • Loop that iterates for validating the path and position whether there is a straight path or a turn required.
      • Else make the visit to the next rows and column to explore the path
    • Define the “isExit ()” method.
      • Return the position.
    • Define the “isDeadEnd ()” method.
      • Return true if the position is dead end
    • Define the “isValid ()” method.
      • Return true is the position is valid
    • Define the “countNeighbors ()” method.
      • Condition to validate the neighbors are with the maze and not with the walls.
      • Return the count

MazeSolver.java

  • Create a class named “MazeSolver”. Inside the class,
    • Define the method “solve ()”
      • Create a new stack
      • Set for the visited intersection is defined.
      • Add the required rows and columns.
      • Loop that iterates for the path
        • Move to the path
      • Loop that iterates for the size of the stack.
        • Assign the required path.
        • Assign the required row and columns
        • Use necessary condition to validate the maze rows and columns and display the appropriate messages.

MazeSolverDemo.java

  • Create a class named “MazeSolverDemo”. Inside the class,
    • Define the method “main ()”
      • Define the maze.
      • Call the method to solve the maze.

Path.java

  • Create a class named “Path”. Inside the class,
    • Define the required variables.
    • Define the method “path ()”
      • Initialize the required variables.
    • Define the method “move ()”
      • Assign the row and columns.
    • Define the method “turn ()”
      • Assign the direction
      • Calculate the ending direction.
    • Define the method “getEndingRow ()”
      • Return the end row.
    • Define the method “getEndingColumn ()”
      • Return the end columns.
    • Define the method “getNextRow ()”
      • Return the next row.
    • Define the method “getNextColumn ()”
      • Return the next columns
    • Define the method “isOpposite ()”
      • Return true if direction are opposite
    • Define the method “isOpposite ()”
      • Return true if direction are opposite
    • Define the method “toString ()”
      • Assign the result.
      • Condition to validate the rows and columns
      • Return the result.

Blurred answer
Students have asked these similar questions
In modern packet-switched networks, including the Internet, the source host segments long, application-layer messages (for example, an image or a music file) into smaller packets and sends the packets into the network. The receiver then reassembles the packets back into the original message. We refer to this process as message segmentation. Figure 1.27 (attached) illustrates the end-to-end transport of a message with and without message segmentation. Consider a message that is 106 bits long that is to be sent from source to destination in Figure 1.27. Suppose each link in the figure is 5 Mbps. Ignore propagation, queuing, and processing delays. a. Consider sending the message from source to destination without message segmentation. How long does it take to move the message from the source host to the first packet switch? Keeping in mind that each switch uses store-and-forward packet switching, what is the total time to move the message from source host to destination host? b. Now…
Consider a packet of length L that begins at end system A and travels over three links to a destination end system. These three links are connected by two packet switches. Let di, si, and Ri denote the length, propagation speed, and the transmission rate of link i, for i = 1, 2, 3. The packet switch delays each packet by dproc. Assuming no queuing delays, in terms of di, si, Ri, (i = 1, 2, 3), and L, what is the total end-to-end delay for the packet? Suppose now the packet is 1,500 bytes, the propagation speed on all three links is 2.5 * 10^8 m/s, the transmission rates of all three links are 2.5 Mbps, the packet switch processing delay is 3 msec, the length of the first link is 5,000 km, the length of the second link is 4,000 km, and the length of the last link is 1,000 km. For these values, what is the end-to-end delay?
how to know the weight to data and data to weight also weight by infomraion gain in rapid miner , between this flow diagram retrieve then selecte attrbuite then set role and split data and decision tree and apply model and peformance ,please show how the operators should be connected:

Chapter 15 Solutions

Big Java Late Objects

Ch. 15.3 - Prob. 11SCCh. 15.3 - Prob. 12SCCh. 15.3 - Prob. 13SCCh. 15.3 - Prob. 14SCCh. 15.3 - Prob. 15SCCh. 15.4 - Prob. 16SCCh. 15.4 - Prob. 17SCCh. 15.4 - Prob. 18SCCh. 15.4 - Prob. 19SCCh. 15.4 - Prob. 20SCCh. 15.5 - Prob. 21SCCh. 15.5 - Prob. 22SCCh. 15.5 - Prob. 23SCCh. 15.5 - Prob. 24SCCh. 15.5 - Prob. 25SCCh. 15.6 - Prob. 26SCCh. 15.6 - Prob. 27SCCh. 15.6 - Prob. 28SCCh. 15.6 - Prob. 29SCCh. 15.6 - Prob. 30SCCh. 15 - Prob. 1RECh. 15 - Prob. 2RECh. 15 - Prob. 3RECh. 15 - Prob. 4RECh. 15 - Prob. 5RECh. 15 - Prob. 6RECh. 15 - Prob. 7RECh. 15 - Prob. 8RECh. 15 - Prob. 9RECh. 15 - Prob. 10RECh. 15 - Prob. 11RECh. 15 - Prob. 12RECh. 15 - Prob. 13RECh. 15 - Prob. 14RECh. 15 - Prob. 15RECh. 15 - Prob. 16RECh. 15 - Prob. 17RECh. 15 - Prob. 18RECh. 15 - Prob. 19RECh. 15 - Prob. 20RECh. 15 - Prob. 21RECh. 15 - Prob. 22RECh. 15 - Prob. 23RECh. 15 - Prob. 24RECh. 15 - Prob. 25RECh. 15 - Prob. 26RECh. 15 - Prob. 1PECh. 15 - Prob. 2PECh. 15 - Prob. 3PECh. 15 - Prob. 4PECh. 15 - Prob. 5PECh. 15 - Prob. 6PECh. 15 - Prob. 7PECh. 15 - Prob. 8PECh. 15 - Prob. 9PECh. 15 - Prob. 10PECh. 15 - Prob. 11PECh. 15 - Prob. 12PECh. 15 - Prob. 13PECh. 15 - Prob. 14PECh. 15 - Prob. 15PECh. 15 - Prob. 16PECh. 15 - Prob. 17PECh. 15 - Prob. 18PECh. 15 - Prob. 19PECh. 15 - Prob. 20PECh. 15 - Prob. 21PECh. 15 - Prob. 22PECh. 15 - Prob. 1PPCh. 15 - Prob. 2PPCh. 15 - Prob. 3PPCh. 15 - Prob. 4PPCh. 15 - Prob. 5PPCh. 15 - Prob. 6PPCh. 15 - Prob. 7PPCh. 15 - Prob. 8PPCh. 15 - Prob. 9PPCh. 15 - Prob. 10PPCh. 15 - Prob. 11PPCh. 15 - Prob. 12PPCh. 15 - Prob. 13PPCh. 15 - Prob. 14PP
Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Database System Concepts
Computer Science
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:McGraw-Hill Education
Text book image
Starting Out with Python (4th Edition)
Computer Science
ISBN:9780134444321
Author:Tony Gaddis
Publisher:PEARSON
Text book image
Digital Fundamentals (11th Edition)
Computer Science
ISBN:9780132737968
Author:Thomas L. Floyd
Publisher:PEARSON
Text book image
C How to Program (8th Edition)
Computer Science
ISBN:9780133976892
Author:Paul J. Deitel, Harvey Deitel
Publisher:PEARSON
Text book image
Database Systems: Design, Implementation, & Manag...
Computer Science
ISBN:9781337627900
Author:Carlos Coronel, Steven Morris
Publisher:Cengage Learning
Text book image
Programmable Logic Controllers
Computer Science
ISBN:9780073373843
Author:Frank D. Petruzella
Publisher:McGraw-Hill Education