EBK ESSENTIAL UNIVERSITY PHYSICS, VOLUM
4th Edition
ISBN: 9780135272947
Author: Wolfson
Publisher: VST
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Question
Chapter 15, Problem 65P
(a)
To determine
The Mar’s surface pressure.
(b)
To determine
The scale height
h 0
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The rate of change of atmospheric pressure P with respect to altitude h is
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Chapter 15 Solutions
EBK ESSENTIAL UNIVERSITY PHYSICS, VOLUM
Ch. 15.1 - What quantity of water has the same mass as 1 m3...Ch. 15.2 - Neglecting friction and other nonconservative...Ch. 15.3 - The density of a rubber ball is three-fifths that...Ch. 15.4 - The photo shows smoke particles tracing...Ch. 15.5 - A large tank is filled with liquid to the level h1...Ch. 15 - Why do your ears pop when you drive up a mountain?Ch. 15 - Water pressure at the bottom of the ocean arises...Ch. 15 - The three containers in Fig. 15.22 are filled to...Ch. 15 - Why is it easier to float in the ocean than in...Ch. 15 - Figure 15.23 shows a cork suspended from the...
Ch. 15 - Why are dams thicker at the bottom than at the...Ch. 15 - Its not possible to breathe through a snorkel from...Ch. 15 - A helium-filled balloon stops rising long before...Ch. 15 - A barge filled with steel beams overturns in a...Ch. 15 - Why do airplanes take off into the wind?Ch. 15 - The density of molasses is 1600kg/m3. Find the...Ch. 15 - Atomic nuclei have densities around 1017kg/m3,...Ch. 15 - Compressed air with mass 8.8 kg is stored in a...Ch. 15 - Whats the weight of a column of air with...Ch. 15 - The diamond anvil is used by scientists and...Ch. 15 - You unbend a paper clip made from 1.5-mm-diameter...Ch. 15 - Whats the density of a fluid whose pressure...Ch. 15 - A research submarine can withstand an external...Ch. 15 - Prob. 19ECh. 15 - A vertical tube open at the top contains 5.0 cm of...Ch. 15 - A child attempts to drink water through a...Ch. 15 - Barometric pressure in the eye of a hurricane is...Ch. 15 - Prob. 23ECh. 15 - A 5.4-g jewel has apparent weight 32 mN when...Ch. 15 - Styrofoams density is 160kg/m3. What percent error...Ch. 15 - A steel drum has volume 0.23 m3 and mass 16 kg....Ch. 15 - Water flows through a 2.5-cm-diameter pipe at 1.8...Ch. 15 - Show that pressure has the units of energy...Ch. 15 - A typical mass flow rate for the Mississippi River...Ch. 15 - Prob. 30ECh. 15 - A typical human aorta, the main artery from the...Ch. 15 - Prob. 32ECh. 15 - Prob. 36ECh. 15 - Example 15.6: You’d like to determine the depth of...Ch. 15 - Prob. 38ECh. 15 - Example 15.6 A fire extinguisher consists of a...Ch. 15 - When a couple with total mass 120 kg lies on a...Ch. 15 - A fully loaded Volvo station wagon has mass 1950...Ch. 15 - Youre stuck in the exit row on a long flight, and...Ch. 15 - A vertical tube 1.0 cm in diameter and open at the...Ch. 15 - Dam breaks present a serious risk of widespread...Ch. 15 - A U-shaped tube open at both ends contains water...Ch. 15 - Prob. 46PCh. 15 - Archimedes purportedly used his principle to...Ch. 15 - Youre testifying in a drunk-driving case for which...Ch. 15 - A glass beaker measures 14 cm high by 5.0 cm in...Ch. 15 - A typical supertanker has mass 2.0 106 kg and...Ch. 15 - A balloon contains gas of density and is to lift a...Ch. 15 - (a) How much helium (density 0.18 kg/m3) is needed...Ch. 15 - Prob. 54PCh. 15 - If the blood pressure in the unobstructed artery...Ch. 15 - Youre a consultant for maple syrup producers. They...Ch. 15 - The water in a garden hose is at 140-kPa gauge...Ch. 15 - The venturi flowmeter shown in Fig. 15.26 is used...Ch. 15 - A 1.0-cm-diameter venturi flowmeter is inserted in...Ch. 15 - A balloons mass is 1.6 g when its empty. Its...Ch. 15 - Blood with density 1.06 g/cm3 and 10-kPa gauge...Ch. 15 - Prob. 62PCh. 15 - In 2012, film producer James Cameron (Terminator,...Ch. 15 - Prob. 65PCh. 15 - Water emerges from a faucet of diameter d0 in...Ch. 15 - Assuming norm.nl atmospheric pressure, how massive...Ch. 15 - Figure 15.28 shows a simplified diagram of a Pitot...Ch. 15 - At a hearing on a proposed wind farm, a...Ch. 15 - A pencil is weighted so it floats vertically with...Ch. 15 - A can of height h and cross-sectional area A0 is...Ch. 15 - Density and pressure in Earths atmosphere are...Ch. 15 - (a) Use the result of Problem 70 to express...Ch. 15 - A circular pan of liquid with density is centered...Ch. 15 - Find the torque that the water exerts about the...Ch. 15 - One vertical wall of a swimming pool is a regular...Ch. 15 - Youre a private investigator assisting a large...Ch. 15 - A plumber conies to your ancient apartment...Ch. 15 - Your class in naval architecture is working on the...Ch. 15 - Prob. 80PPCh. 15 - Prob. 81PPCh. 15 - Prob. 82PPCh. 15 - Prob. 83PP
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- The pressure on Earth's atmosphere as a function of height y above sea level can be determined by assuming g to be constant and that the density of air is proportional to the pressure, i.e., px P. Note that this assumption is not very accurate since temperature and other weather effects can influence pressure. [Hint: Po = 1.013 × 105 N/m², po = 1.29 kg x m-³] (1) Start by finding a relation between the pressure Po and the density of air po at 0° at sea level (y=0) and the pressure P and density p at height y. Using this relation find an expression for p as a function of P, i.e., p = p(P). (2) Find the pressure as a function y. (3) At what altitude above sea level is the atmospheric pressure equal to half the pressure at sea level?arrow_forwardAtmospheric pressure. Atmospheric pressure P at altitude a is given by P = Poe¬0.00005a where Po is the pressure at sea level. Assume that Po = 14.7 lb/in´ (pounds per square inch). a) Find the pressure at an altitude of 1000 ft. b) Find the pressure at an altitude of 20,000 ft. c) At what altitude is the pressure 14.7 lb/in? d) Find the rate of change of the pressure, and interpret its meaning.arrow_forwardThe density of the atmosphere varies drastically with height, but you can use an average density from sea floor to the space in order to calculate its height. If we approximate this average density to be = 1 Kg/m³, what would be height of the atmosphere? HINT: Since the atmosphere is a fluid (in gas form), you can use the hydrostatic pressure formula (P pgh), just solve for h and use P = 1 atm. BTW, this is how the edge of space is defined, if you make it pass the height of the atmosphere you have reached space :)arrow_forward
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