Chapter 15, Problem 64RQ

Aluminum chloride, ${\text{AlCl}}_{\text{3}}$, forms molecules with itself with the formula ${\text{Al}}_{\text{2}}{\text{Cl}}_{\text{6}}$. Its structure is

Use Lewis structures to show how the reaction ${\text{2A1C1}}_{\text{3}}\stackrel{}{\to }{\text{Al}}_{\text{2}}{\text{Cl}}_{\text{6}}$ is a Lewis acid-base reaction.