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Concept explainers
62. Which of the following equations might have the graph shown? (More than one answer is possible.)
a.
b.
c.
d.
e.
f.
g.
h.
![Check Mark](/static/check-mark.png)
To find: Which of the following equations might have the graph (More than one answer is possible).
Answer to Problem 62AYU
Solution:
(b),(e) and (g) may represent the given graph.
Explanation of Solution
Given:
a.
b.
c.
d.
e.
f.
g.
h.
Condition 1: The center of the circle is on the . Therefore, the of the center is 0.
Condition 2: The center of the circle is to the left of . Therefore, the of the center is negative.
Only the following equations satisfy the above conditions:
Equation (b),(d), (e) and (g)
Condition 3: From the given graph, we can see that the radius > Distance of the nearest point from the.
After adding(radius) on both sides of the Inequality, we can write
.
Equation (b)
Center of the circle is . Hence, the distance of the center from the is 2 units.
Radius is and .
Therefore equation (b) satisfies the condition 3 and it may represent the given graph.
Equation (d)
Center of the circle is . Hence, the distance of the center from the is 2 units.
Radius is and .
Therefore equation (d) does not satisfy the condition 3 and it may not represent the given graph.
Equation (e)
The above equation can be written as
The center of this circle is
Distance of the center from the is 5 units.
Radius is 3 and .
Therefore the equation(e) satisfies the condition 3 and may it represent the given graph.
Equation (g)
The above equation can be written as
The center of this circle is
Distance of the center from the is units.
Radius is and .
Therefore the equation (g) satisfies the condition 3 and may it represent the given graph.
Chapter 1 Solutions
Precalculus Enhanced with Graphing Utilities
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