Chapter 1, Problem 6CT

To determine

To find: The intercepts and label them on graph, using a graphing utility.

Answer to Problem 6CT

  

Explanation of Solution

Given information: $y=x^2-5$

Calculation:

  $\begin{array}{c}-x^3+7x-2=x^2+3x-3\\ -x^3-x^2+7x-3x-2+3=0\\ -x^3-x^2+4x+1=0\\ x^3+x^2-4x-1=0\end{array}$

Use graphing device to graph the function $x^3+x^2-4x-1=0$ .

Graph: Sketch the graph using graphing utility.

Step 1: Press WINDOW button to access the Window editor.

Step 2: Press $\boxed{\text{Y=}}$ button.

Step 3: Enter the expression $x^3+x^2-4x-1=0$ which is required to graph.

Step 4: Press GRAPH button to graph the function and adjust the windows according to the graph.

The graph is obtained as:

  

Hence, From the graph we obtain,

X-intercept = $\text{1}\text{.7 and -1}\text{.7}$ and Y-intercept = $-1$