EBK BIOLOGY
6th Edition
ISBN: 8220106777640
Author: Maier
Publisher: PEARSON
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Chapter 15, Problem 5LTB
According to the graph shown here, the
Time
- 0 flies;
- 100 flies;
- 150 flies;
- between 100 and 150 flies;
- impossible to determine
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Below is the colony diameter for each yeast culture grown on PDA and AcA incubated at 35°C measured at Day 7. From the data presented above, what could you observe about the growth of the yeast cultures on PDA and AcA? Cite possible reasons behind this.
SPREAD PLATE
See the follow up procedure for determining colony counts and express the number of colony forming units
(CFU) in scientific notation. Record "TNTC" for plates with colonies that are too numerous to count.
CFU/mL-Use scientific notation
DILUTION
1:107
1:108
COLONY COUNT
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label the pellicle and daughter paramecia of paramecium PLEASE DRAW ON THE PICTURE, EDIT IT AND PUT ARROW
Chapter 15 Solutions
EBK BIOLOGY
Ch. 15 - Prob. 1LTBCh. 15 - Prob. 2LTBCh. 15 - Prob. 3LTBCh. 15 - Prob. 4LTBCh. 15 - According to the graph shown here, the carrying...Ch. 15 - All of the following are density-dependent factors...Ch. 15 - In contrast to nonhuman populations, human...Ch. 15 - Populations that rely on stored resources are...Ch. 15 - The current carrying capacity of Earth for the...Ch. 15 - Prob. 10LTB
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- The following image shows part of counting chamber you used to estimate cell viability for yeast cells. If the dilution factor you used was 1:200, and the total sample volume was 5 ml, then calculate the cell viability, the cell density and the total cell.arrow_forwardYour labmate tells you that you need to go back to the original colony each time you streak a new quadrant on your streak plate to achieve the goal of the lab. Is your labmate correct (does this achieve the goal)? Why or why not? (2-3 sentences max)arrow_forwardplates normally show a 10-fold decrease in colony number through the dilutions, e.g. 500 on Plate D, ~50 on E, ~5 on F, and maybe none on G. If this was not observed, what human errors might have contributed to inconsistent serial dilution? How could one ensure proper serial dilution technique for future labs?arrow_forward
- Encode the word true if the statement is correct. If the underline word/s is incorrect, then correct the underlined word/s that makes the statement wrong by encoding the correct answer beside false. Answers must be encoded in capital letters 1. When Grammia incorrupta caterpillars are infected by a parasitoid, they show an increased preference for acidic toxins found in larval food plants, and by choosing to eat these toxic plants when infected, are able to increase survival.arrow_forwardlabel the pellicle and daughter paramecia of paramecium PLEASE DRAW ON THE PICTURE, USE ARROW AND DRAWarrow_forwardRoom air is collected on a plate using a sampler that pulls 50 L per minute. If 11 fungal colonies grow after 4 minutes of sampling, what is the propagule forming count per L of air ? You do not need to use an MPN (Probability) table for this sampler. Round off your answer to one decimal place only Your Answer: Answerarrow_forward
- A medium was inoculated with 5 * 106 cells/ml of Escherichiacoli cells. Following a 1-h lag, the population grewexponentially for 5 h, after which the population was 5.4 * 109cells/ml. Calculate g and k for this growth experiment.arrow_forward+ Slider1 + Slider2 108 107 106 105 104 30 60 90 120 150 180 210 240 Time in minutes Determine the following: 1. The shortest generation time (shortest cell doubling time, in mins) of the organism 2. The growth rate of the organism at the point where its generation time is shortest 3. Describe the organism's growth curve using the numerical data you obtained from your calculations of generation time and growth rate. Cell numbersarrow_forwardAs shown in this diagram, you perform a ten-fold serial dilution of a culture to determine the number of colony forming units (CFU) per mL it contains. You do a plate count with these growth results (no. of colonies for each dilution): 1:10 too many to count; 1:100 too many to count; 1:1,000 174; 1:10,000 23; 1:100,000 no growth. The number of CFU per mL in the original culture was: 1 ml 1 ml Original inoculum Dilutions 9 ml broth in each tube 1:10 1 ml 174,000 1:100 1 ml 1 ml 1 ml 1:1000 1 ml 1:10,000 1 ml None of the other four answers (Correct answer not given) 1,000 230,000 174 1 ml 1:100,000 1 mlarrow_forward
- As shown in this diagram, you perform a ten-fold serial dilution of a culture to determine the number of colony forming units (CFU) per mL it contains. You do a plate count with these growth results (no. of colonies for each dilution): 1:10 too many to count; 1:100 too many to count; 1:1,000 312; 1:10,000 38; 1:100,000 no growth. The number of CFU per mL in the original culture was: A. 38 B. 380,000 C. 38,000 D. None of the other four answers (Correct answer not given) E. 10,000arrow_forwardSexual spore production by Penicillium is by a zygosporangium True Falsearrow_forwardWrite a short discussion based on the graph and calculate mean growth rate and mean generation timearrow_forward
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