Organic Chemistry
Organic Chemistry
7th Edition
ISBN: 9780321803221
Author: Paula Y. Bruice
Publisher: Prentice Hall
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Chapter 15, Problem 56P
Interpretation Introduction

Interpretation:

The compound with the molecular formula C7H14O by the proton-coupled 13C NMR has to be identified.

Concept introduction:

The signals in the spectrum of a compound are proportional to the number of carbons that are present in the different environment within the molecule.  The carbon which is present in the electron-rich environment shows a signal at a lower frequency and vice-versa.  Therefore, the carbons that are present nearest to the electron-withdrawing groups produce a high-frequency signal.

When a spectrometer is run in a proton-coupled mode, then the signals in 13C NMR spectra is split by the protons attached to a particular carbon.

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Chapter 15 Solutions

Organic Chemistry

Ch. 15.6 - Prob. 11PCh. 15.7 - Prob. 12PCh. 15.7 - Prob. 13PCh. 15.7 - Without referring to Table 14.1, label the proton...Ch. 15.8 - [18]-Annulene shows two signals in its 1H NMR...Ch. 15.9 - How would integration distinguish the 1H NMR...Ch. 15.9 - Which of the following compounds is responsible...Ch. 15.10 - Prob. 19PCh. 15.10 - Explain how the following compounds, each with the...Ch. 15.10 - The 1H NMR spectra of two carboxylic acids with...Ch. 15.11 - Draw a diagram like the one shown in Figure 14.12...Ch. 15.12 - Indicate the number of signals and the...Ch. 15.12 - How can their 1H NMR spectra distinguish the...Ch. 15.12 - Identify each compound from its molecular formula...Ch. 15.12 - Prob. 27PCh. 15.12 - Propose structures that are consistent with the...Ch. 15.12 - Describe the 1H NMR spectrum you would expect for...Ch. 15.13 - Prob. 30PCh. 15.13 - Identify the compound with molecular formula...Ch. 15.14 - Prob. 32PCh. 15.15 - a. For the following compounds, which pairs of...Ch. 15.17 - Explain why the chemical shift of the OH proton of...Ch. 15.17 - Prob. 37PCh. 15.17 - Prob. 38PCh. 15.17 - Prob. 39PCh. 15.20 - Answer the following questions for each compound:...Ch. 15.20 - Prob. 41PCh. 15.20 - How can 1,2-, 1,3-, and 1,4-dinitrobenzene be...Ch. 15.20 - Identify each compound below from its molecular...Ch. 15.22 - Prob. 44PCh. 15.22 - What does cross peak X in Figure 14.34 tell you?Ch. 15 - Prob. 46PCh. 15 - Draw a spitting diagram for the Hb proton and give...Ch. 15 - Label each set of chemically equivalent protons,...Ch. 15 - Match each of the 1H NMR spectra with one of the...Ch. 15 - Determine the ratios of the chemically...Ch. 15 - How can 1H NMR distinguish between the compounds...Ch. 15 - Prob. 52PCh. 15 - The 1H NMR spectra of three isomers with molecular...Ch. 15 - Prob. 54PCh. 15 - Prob. 55PCh. 15 - Prob. 56PCh. 15 - Compound A, with molecular formula C4H9Cl, shows...Ch. 15 - The 1H NMR spectra of three isomers with molecular...Ch. 15 - Would it be better to use 1H NMR or 13C NMR...Ch. 15 - There are four esters with molecular formula...Ch. 15 - An alkyl halide reacts with an alkoxide ion to...Ch. 15 - Identity each of the following compounds from its...Ch. 15 - Identity each of the following compounds from its...Ch. 15 - Prob. 64PCh. 15 - How can the signals in the 6.5 to 8.1 ppm region...Ch. 15 - The 1H NMR spectra of two compounds, each with...Ch. 15 - Draw a splitting diagram for the Hb proton if Jbc...Ch. 15 - Sketch the following spectra that would be...Ch. 15 - How can 1H NMR be used to prove that the addition...Ch. 15 - Identity each of the following compounds from its...Ch. 15 - Dr. N. M. Arr was called in to help analyze the 1H...Ch. 15 - Calculate the amount of energy (in calories)...Ch. 15 - The following 1H NMR spectra are four compounds,...Ch. 15 - When compound A (C5H12O) is treated with HBr, it...Ch. 15 - Identity each of the following compounds from its...Ch. 15 - Identify each of the following compounds from its...Ch. 15 - Identity the compound with molecular formula...Ch. 15 - Identify the compound with molecular formula C6H14...
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NMR Spectroscopy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=SBir5wUS3Bo;License: Standard YouTube License, CC-BY