Explanation It is given that: The mass of SO 3 at equilibrium is 1.17 g . The mass of O 2 at equilibrium is 0.105 g . The equilibrium constant in terms of pressure is 3.0 × 10 4 . The temperature of the reaction mixture is 700 K . The volume of the vessel/reaction mixture is 2.00 L . The reaction is, 2SO 2 ( g ) + O 2 ( g ) ⇌ 2SO 3 ( g ) The change in the number of moles is calculated as, Δ n = n product − n reactant Where, Δ n is the change in the number of moles. n product is the total number of moles of product. n reactant is the total number of moles of reactant. Substitute the value of n product and n reactant in the above equation. Δ n = 2 − ( 2 + 1 ) = − 1 The equilibrium constant, K c of the given reaction at 700 K is calculated by the formula, K p = K c ( R T ) Δ n K c = K p ( R T ) Δ n Where, K c is the equilibrium constant of the given reaction at 700 K . K p is the equilibrium constant in terms of pressure at 700 K . R is the gas constant ( 0.08206 atm ⋅ L / mol ⋅ K ) . T is the temperature of the reaction mixture. Substitute the value of K p , R and T in the above equation. K c = 3.0 × 10 4 atm − 1 ( ( 0.08206 atm ⋅ L / mol ⋅ K ) × ( 700 K ) ) − 1 = 3.0 × 10 4 atm − 1 ( 57.442 atm ⋅ L / mol ) − 1 = 172.3 × 10 4 L/mol = 172.3 × 10 4 M − 1 Molar mass of O 2 is calculated as, 2 × ( 15.999 g/mol ) = 31.998 g/mol Number of moles of O 2 at equilibrium is calculated by the formula., Moles of O 2 = Mass of O 2 Molar mass of O 2 Substitute the value of the mass of O 2 and molar mass of O 2 in the above equation. Moles of H 2 = 0.105 g 31.998 g/mol = 0.00328 mol The concentration (molarity) of O 2 at equilibrium is calculated by the formula, Molarity = Moles of O 2 Volume of reaction mixture Substitute the value of moles of O 2 and the volume of the reaction mixture in the above equation. Molarity = 0.00328 mol 2.00 L = 1.64 × 10 − 3 M In a similar way, the concentration of SO 3 at equilibrium is 7.3 × 10 − 3 M

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Chapter 15, Problem 50E

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The mass of SO2 present in the reaction vessel.

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Chapter 15, Problem 49E

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Chapter 15 Solutions

CHEMISTRY THE CENTRAL SCIENCE >EBOOK<

Ch. 15.2 - Prob. 15.1.1PE Ch. 15.2 - Prob. 15.1.2PE Ch. 15.2 - Prob. 15.2.1PE Ch. 15.2 - Prob. 15.2.2PE Ch. 15.3 - Prob. 15.3.1PE Ch. 15.3 - Practice Exercise 2 For the reaction H2 (g) + I2...Ch. 15.3 - Prob. 15.4.1PE Ch. 15.3 - Prob. 15.4.2PE Ch. 15.4 - Prob. 15.5.1PE Ch. 15.4 - Prob. 15.5.2PE

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The mass of SO 2 present in the reaction vessel.

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To determine: The mass of SO2 present in the reaction vessel.

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Chapter 15 Solutions

To determine:
The mass of SO2 present in the reaction vessel.