(a) Explanation Given info: The weight of the block in alcohol is 25.7 N and the weight of the block in water is 25.0 N . Write the expression for weight of block in water. W w = W ( 1 − ρ w ρ b ) (1) Here, W is the weight of block in air. W w is the weight of block in water. ρ w is the density of water. ρ b is the density of block. Write the expression for weight of block in alcohol. W a = W ( 1 − ρ a ρ b ) (2) Here, W is the weight of block in air. W a is the weight of block in alcohol. ρ a is the density of alcohol. Divide equation (1) by (2). W w W a = W ( 1 − ρ w ρ b ) W ( 1 − ρ a ρ b ) Rearrange the above equation to get density of block. ρ b = W a ρ w − W w ρ a W a − W w Substitute 25.7 N for W a , 1000 kg / m 3 for ρ w , 806 kg / m 3 for ρ a and 25.0 N for W w . ρ b = ( 25.7 N ) ( 1000 kg / m 3 ) − ( 25.0 N ) ( 806 kg / m 3 ) ( 25.7 N ) − ( 25.0 N ) = 7 (b) To determine The density of the block.

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ISBN: 9780134051802

Author: Walker

Publisher: PEARSON

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Density of Solids

The density of a substance refers to how much matter is present in a given amount of space. It is expressed as the ratio of the mass of the substance to its volume.

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Chapter 15, Problem 44PCE

(a)

To determine

The volume of the block.

(b)

To determine

The density of the block.

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Chapter 15, Problem 43PCE

Chapter 15, Problem 45PCE

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Physics (5th Edition)

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The volume of the block.

Solution Summary: The author explains that the volume of the block is 3.68. Write the expression for weight of block in water.

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The volume of the block.

The density of the block.

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Chapter 15 Solutions