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Concept explainers
Interpretation: The dissolution of ionic compounds in water and how positive and negative ions are prevented from getting recombined need to be explained
Concept introduction: Ionic substances are soluble in water and hence they are called electrolyte. Depending on nature of electrolyte (which element forms cation and anion) the extent of solubility varies.
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Answer to Problem 3A
An ionic compound dissolves in water by the virtue of ionic interaction of ions and water. Water molecules wrap the ions and thus prevent the ions from getting recombined.
Explanation of Solution
When an ionic compound dissolves in water, the ions leave their ordered arrangement of crystal lattice. The energy needed to break the ions from 1 mol ionic compound from the crystal lattice is called lattice energy. After the ions get dispersed in water, it undergoes hydration with water molecules and the energy released when 1 mol of ionic compound undergoes hydration is called enthalpy of hydration.
When enthalpy of hydration is greater than lattice energy the ionic compound dissolves in water. Conversely, we can say when ion-water interaction is stronger than ion-ion and water-water interaction the solubility of ionic compound is favored.
Due to electronegativity difference of oxygen and hydrogen a dipole is generated in water molecule where oxygen acquires partial negative charge and hydrogen acquires partial positive charge. When ions dissolves in water, negative ion are attracted to positive end of hydrogen and positive ions are attracted to negative end of oxygen. Hence, the water molecule makes a shield around ions which prevents their recombination again into solid ionic compound.
An ionic compound dissolves in water by the virtue of ionic interaction of ions and water. Water molecules wrap the ions and thus prevent the ions from getting recombined.
Chapter 15 Solutions
World of Chemistry, 3rd edition
- I don't understand what to put for final step. Does that just mean termination? And would a radical form when I add bromine to ch2 between the rings?arrow_forwardNonearrow_forward11 1 Which one of the following compounds would show a proton NMR signal at the highest chemical shift? (7pts) cl @amitabh CI CI d) Cl CICIarrow_forward
- Nonearrow_forwardH2SO4 (cat.), H₂O 100 °C NH₂arrow_forwardX Draw the major products of the elimination reaction below. If elimination would not occur at a significant rate, check the box under the drawing area instead. ది www. Cl + OH Elimination will not occur at a significant rate. Click and drag to start drawing a structure.arrow_forward
- Nonearrow_forward1A H 2A Li Be Use the References to access important values if needed for this question. 8A 3A 4A 5A 6A 7A He B C N O F Ne Na Mg 3B 4B 5B 6B 7B 8B-1B 2B Al Si P 1B 2B Al Si P S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe * Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn Fr Ra Ac Rf Ha ****** Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr Analyze the following reaction by looking at the electron configurations given below each box. Put a number and a symbol in each box to show the number and kind of the corresponding atom or ion. Use the smallest integers possible. cation anion + + Shell 1: 2 Shell 2: 8 Shell 3: 1 Shell 1 : 2 Shell 2 : 6 Shell 1 : 2 Shell 2: 8 Shell 1: 2 Shell 2: 8arrow_forwardNonearrow_forward
- IV. Show the detailed synthesis strategy for the following compounds. a. CH3CH2CH2CH2Br CH3CH2CCH2CH2CH3arrow_forwardDo the electrons on the OH participate in resonance with the ring through a p orbital? How many pi electrons are in the ring, 4 (from the two double bonds) or 6 (including the electrons on the O)?arrow_forwardPredict and draw the product of the following organic reaction:arrow_forward
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