Explanation Procedure used: Procedure for Synthetic Division: “1. Write the coefficients of f ( x ) . Be certain that the powers are in descending order and that zeros are inserted for missing powers. 2. Carry down the left coefficient, then multiply it by r , and place this product under the second coefficient of the top line. 3. Add the two numbers in the second column and place the result below. Multiply this sum by r and place the product under the third coefficient of the top line. 4. Continue this process until the bottom row has as many numbers as the top row”. Calculation: It is given that r 1 = r 2 = r 3 = − 1 are the triple root of the equation s 5 − 3 s 4 − 2 3 − 11 s 2 − 12 s − 4 = 0 . The powers of s are in descending order, write down the coefficient of f ( s ) = s 5 − 3 s 4 − 2 3 − 11 s 2 − 12 s − 4 and zeros are inserted for missing powers and then place 1 to the right end. 1 3 − 1 − 11 − 12 − 4 − 1 Bring down the left coefficient 1 to the bottom line and multiply it by –1, and place the product value –1 under the second coefficient 3 of the top line. Proceed in this similar manner, to find the quotient and remainder. 1 3 − 1 − 11 − 12 − 4 − 1 − 1 − 2 3 8 4 _ 1 2 − 3 − 8 − 4 0 − 1 − 1 − 1

Student Solutions Manual For Basic Technical Mathematics And Basic Technical Mathematics With Calculus

11th Edition

ISBN: 9780134434636

Author: Allyn J. Washington, Richard Evans

Publisher: PEARSON

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Chapter 15, Problem 33RE

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The remaining roots of the equation s5−3s4−23−11s2−12s−4=0 using synthetic division.

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Chapter 15, Problem 32RE

Chapter 15, Problem 34RE

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Chapter 15 Solutions

Student Solutions Manual For Basic Technical Mathematics And Basic Technical Mathematics With Calculus

Ch. 15.1 - Use the factor theorem to determine whether t − 2...Ch. 15.1 - Prob. 2PE Ch. 15.1 - Prob. 3PE Ch. 15.1 - Prob. 4PE Ch. 15.1 - Prob. 1E Ch. 15.1 - Prob. 2E Ch. 15.1 - In Exercises 1–4, make the given changes in the...Ch. 15.1 - Prob. 4E Ch. 15.1 - Prob. 5E Ch. 15.1 - Prob. 6E

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The remaining roots of the equation s 5 − 3 s 4 − 2 3 − 11 s 2 − 12 s − 4 = 0 using synthetic division.

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The remaining roots of the equation s5−3s4−23−11s2−12s−4=0 using synthetic division.

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Chapter 15 Solutions