The monomer which gives greater yield polymer, 5-hydroxypentanoic acid or 6-hydroxyhexanoic acid has to be explained. Concept Introduction: Polymers : Monomers combine together to form polymers. Monomers are the repeating units of small molecules which link together to form polymers and the process is called as polymerization . Two types of polymers: Synthetic and biopolymers. DNA is an example for biopolymer and these type of polymers are synthesized by cells. Polymers synthesized by scientists are called synthetic polymers and some examples are nylon, polyester etc. Two types of synthetic polymers: Chain-growth polymers or addition polymers and Step-growth polymers or Condensation polymers. Chain growth polymers are formed by the monomer addition to the end of a growing chain. Step-growth polymers are formed by combining monomers by removing small molecules of water or alcohol.

Question

Want to see the full answer?

Answer 1

Question

Chapter 15, Problem 31P

Interpretation Introduction

Interpretation:

The monomer which gives greater yield polymer, 5-hydroxypentanoic acid or 6-hydroxyhexanoic acid has to be explained.

Concept Introduction:

Polymers:

Monomers combine together to form polymers. Monomers are the repeating units of small molecules which link together to form polymers and the process is called as polymerization.

Two types of polymers:

Synthetic and biopolymers.

DNA is an example for biopolymer and these type of polymers are synthesized by cells.

Polymers synthesized by scientists are called synthetic polymers and some examples are nylon, polyester etc.

Two types of synthetic polymers:

Chain-growth polymers or addition polymers and Step-growth polymers or Condensation polymers.

Chain growth polymers are formed by the monomer addition to the end of a growing chain.

Step-growth polymers are formed by combining monomers by removing small molecules of water or alcohol.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Part VII. The H-NMR of a compound with molecular formula C5 H 10 O2 is given below. Find the following: (a) The no. of protons corresponding to each signal in the spectra (6) Give the structure of the compound and assign the signals to each proton in the compound. a 70.2 Integration Values C5H10O2 b 47.7 C 46.5 d 69.5 3.6 3.5 3.4 3.3 3.2 3.1 3.0 2.9 2.8 2.7 2.6 2.5 2.4 2.3 2.2 2.1 2.0 Chemical Shift (ppm) 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1 1.0 0.9 0.8

Part 111. 1 H-NMR spectrum of a compound with integration values in red is given below. Answer the following: (a) write the signals in the 'H-NMR spectrum to the corresponding protons on the structure of the molecule below. (b) Identify the theoretical multiplicities for each proton in the compound. Also give the possible. complex splitting patterns assuming J values are not similar. там Br 22 2 3 6 4 7.2 7.0 6.8 6.6 6.4 6.2 6.0 5.8 5.6 5.4 5.2 5.0 4.8 4.6 4.4 4.2 4.0 3.8 3.6 3.4 3.2 3.0 2.8 2.6 2.4 2.2 2.0 1.8 1.6 1.4 1.2 1.0 0.8 0 Chemical Shift (ppm) ra. Br 2 3 6 6 2.5 2.4 2.3 2.2 2.1 2.0 1.9 1.8 1.7 1.6 1.5 1.4 1.3 1.2 1.1 1.0 0.9 0.8 Chemical Shift (ppm) 2 2 Br 7.3 7.2 7.1 7.0 6.9 6.7 6.6 6.5 6.4 6.3 6.2 6.1 6.0 Chemical Shift (ppm) 5.9 5.8 5.7 5.5 5.4 5.3 5.2 5.0 4.9

1600° 1538°C 1493°C In the diagram, the letter L indicates that it is a liquid. Indicate its components in the upper region where only L is indicated. The iron-iron carbide phase diagram. Temperature (°C) 1400 8 1394°C y+L 1200 2.14 y, Austenite 10000 912°C 800a 0.76 0.022 600 400 (Fe) a, Ferrite Composition (at% C) 15 1147°C a + Fe3C 2 3 Composition (wt% C) L 2500 4.30 2000 y + Fe3C 727°C 1500 Cementite (Fe3C) 1000 4 5 6 6.70 Temperature (°F)