Chapter 15, Problem 31A

To determine

To Compute: The width of the canyon.

Answer to Problem 31A

  $W=514.5\text{ m}$

Explanation of Solution

Given:

Time interval, $\Delta t=3.0\text{ s}$

Speed of sound wave, $V=343\text{ m/s}$

Formula used:

  $d=V\times \Delta t$

Where,

  $d=$ Distance.

  $\Delta t=$ Time.

  $V=$ Speed of sound wave.

Calculation:

Plugging in the given values:

  $\begin{array}{c}d=343\times 3.0\\ =1029\text{ m}\end{array}$

Since, $d$ is round trip distance, therefore, width of the canyon would be half of the round-trip distance.

  $\begin{array}{c}W=\frac{d}{2}\\ =\frac{1029}{2}\\ =514.5\text{ m}\end{array}$

Conclusion:

Width of the canyon: 514.5 m