Bundle: Chemistry In Focus: A Molecular View Of Our World, 6th + Owlv2 6-month Printed Access Card
6th Edition
ISBN: 9781305618374
Author: Nivaldo J. Tro
Publisher: Cengage Learning
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Question
Chapter 15, Problem 19E
Interpretation Introduction
Interpretation:
The reason behind the statement “Drain cleaners and toilet bowl cleaners should never be mixed” is to be explained.
Concept Introduction:
A household product such as toilet bowl cleaner is very reactive as it is acidic in nature. It is very much corrosive in nature and is available in both solid and liquid forms.
Drain cleaners are very reactive, and they help in removing clogs from the drains. They are corrosive substances.
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Students have asked these similar questions
A 0.10 M solution of acetic acid (CH3COOH, Ka = 1.8 x 10^-5) is titrated with a 0.0250 M solution of magnesium hydroxide (Mg(OH)2). If 10.0 mL of the acid solution is titrated with 20.0 mL of the base solution, what is the pH of the resulting solution?
For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3)
→
Give the expression for the acceptable rate.
→
→
(A).
d[N205]
dt
==
2k,k₂[N₂O₂]
k₁+k₁₂
(B).
d[N2O5]
=-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³
dt
(C).
d[N2O5]
=-k₁[N₂O] + k [NO] - k₂[NO] [NO]
d[N2O5]
(D).
=
dt
= -k₁[N2O5] - k¸[NO][N₂05]
dt
Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
For the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed:
N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3)
→
Give the expression for the acceptable rate.
→
→
(A).
d[N205]
dt
==
2k,k₂[N₂O₂]
k₁+k₁₂
(B).
d[N2O5]
=-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³
dt
(C).
d[N2O5]
=-k₁[N₂O] + k [NO] - k₂[NO] [NO]
d[N2O5]
(D).
=
dt
= -k₁[N2O5] - k¸[NO][N₂05]
dt
Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard
the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.
Chapter 15 Solutions
Bundle: Chemistry In Focus: A Molecular View Of Our World, 6th + Owlv2 6-month Printed Access Card
Ch. 15 - Prob. 15.1YTCh. 15 - Prob. 1SCCh. 15 - Prob. 2SCCh. 15 - Prob. 3SCCh. 15 - Prob. 1ECh. 15 - Prob. 2ECh. 15 - Prob. 3ECh. 15 - Prob. 4ECh. 15 - Prob. 5ECh. 15 - Prob. 6E
Ch. 15 - Prob. 7ECh. 15 - Prob. 8ECh. 15 - Prob. 9ECh. 15 - Prob. 10ECh. 15 - Prob. 11ECh. 15 - Prob. 12ECh. 15 - Prob. 13ECh. 15 - Define eutrophication.Ch. 15 - Prob. 15ECh. 15 - Prob. 16ECh. 15 - Prob. 17ECh. 15 - Prob. 18ECh. 15 - Prob. 19ECh. 15 - What are the three types of interactions that...Ch. 15 - Prob. 21ECh. 15 - Prob. 22ECh. 15 - Prob. 23ECh. 15 - Prob. 24ECh. 15 - Prob. 25ECh. 15 - Prob. 26ECh. 15 - Prob. 27ECh. 15 - Prob. 28ECh. 15 - Prob. 29ECh. 15 - How do sunscreens protect your skin from the Suns...Ch. 15 - Prob. 31ECh. 15 - Prob. 32ECh. 15 - Prob. 33ECh. 15 - Prob. 34ECh. 15 - Prob. 35ECh. 15 - Prob. 36ECh. 15 - Prob. 37ECh. 15 - Prob. 38ECh. 15 - Prob. 39ECh. 15 - Prob. 40ECh. 15 - Prob. 41ECh. 15 - Prob. 42ECh. 15 - Prob. 43ECh. 15 - Prob. 44ECh. 15 - Prob. 45ECh. 15 - Prob. 46ECh. 15 - The salt bridges that hold hair protein (keratin)...Ch. 15 - Prob. 48ECh. 15 - The hydrochloric acid present in toilet bowl...Ch. 15 - Prob. 50ECh. 15 - Prob. 51ECh. 15 - Prob. 52ECh. 15 - Prob. 53ECh. 15 - Prob. 54ECh. 15 - Prob. 55ECh. 15 - Prob. 56ECh. 15 - Prob. 57ECh. 15 - Prob. 58ECh. 15 - Prob. 59ECh. 15 - Prob. 60ECh. 15 - Prob. 61ECh. 15 - Prob. 62ECh. 15 - Prob. 64ECh. 15 - Prob. 65E
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