Explanation Given information: The shear failure occurred along the cylinder BC and the tension failure along the frustrum AB . Calculation: Tensile stress acting along the frustum AB is 3 MPa. Shear stress acting along the cylinder BC is 4.5 MPa. Find the cross sectional area of the frustum as shown below. A = 2 π x ¯ L = 2 π ( 0.025 + 0.025 ) ( 0.05 2 + 0.05 2 ) = 0.02221 m 2 Find the cross sectional area of the cylinder as shown below. A C = π × 0.05 × 0.03 = 0.004712 m 2 Find the loading along AB and BC as shown below. For the frustum AB . σ = P A Here, P is the force acting along AB and A is the cross sectional area of the frustum. Substitute 3 MPa for σ , F 1 for P , and 0.02221 m 2 for A . 3 MPa × 10 3 kN / m 2 1 MPa = F 1 0.02221 m 2 F 1 = 66.63 kN For the cylinder BC . τ avg = V A C Here, V is the shear force acting along BC and A C is the cross sectional area of the cylinder

9th Edition

ISBN: 9780133254426

Author: Russell C. Hibbeler

Publisher: Prentice Hall

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Chapter 1.5, Problem 1.58P

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To calculate: The force P applied to the bolt.

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Chapter 1.5, Problem 1.57P

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