An AISI 1018 steel has a yield strength, S, = 295 MPa. Under the plane stress condition the stresses at a critical point are determined to be: σ = -30 MPa,σ = -65 MPa and Txy = 40 MPa 1. Determine the principle stresses at the critical point (5 points) 2. Determine the factor of safety, using the distortion-energy theory (5 points) 3. Determine maximum shear stress (in-lane and out-of-plane) (5 points) 4. Determine the factor of safety, using the maximum shear stress theory (5 points)

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter8: Applications Of Plane Stress (pressure Vessels, Beams, And Combined Loadings)
Section: Chapter Questions
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An AISI 1018 steel has a yield strength, S, = 295 MPa. Under the plane stress condition the stresses at a critical point are determined
to be: σ = -30 MPa,σ = -65 MPa and Txy = 40 MPa
1. Determine the principle stresses at the critical point (5 points)
2. Determine the factor of safety, using the distortion-energy theory (5 points)
3. Determine maximum shear stress (in-lane and out-of-plane) (5 points)
4. Determine the factor of safety, using the maximum shear stress theory (5 points)
Transcribed Image Text:An AISI 1018 steel has a yield strength, S, = 295 MPa. Under the plane stress condition the stresses at a critical point are determined to be: σ = -30 MPa,σ = -65 MPa and Txy = 40 MPa 1. Determine the principle stresses at the critical point (5 points) 2. Determine the factor of safety, using the distortion-energy theory (5 points) 3. Determine maximum shear stress (in-lane and out-of-plane) (5 points) 4. Determine the factor of safety, using the maximum shear stress theory (5 points)
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