EBK ORGANIC CHEMISTRY: PRINCIPLES AND M
EBK ORGANIC CHEMISTRY: PRINCIPLES AND M
2nd Edition
ISBN: 9780393543971
Author: KARTY
Publisher: VST
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Chapter 15, Problem 15.7YT
Interpretation Introduction

Interpretation:

For each compound from Table 15-1 that contains only carbon and hydrogen, the number of conjugated π bonds that make up the largest π system is to be determined and this number is to be compared to the compound’s longest-wavelength λmax.

Concept introduction:

A compound containing at least one π bond absorbs photons in the UV region. The UV spectrum of such compounds contains one or more bands or peaks. The wavelength at which the absorbance is maximum is λmax for that band or peak. The longest wavelength peak (λmax) corresponds to the HOMO-LUMO transition as it requires the lowest energy. The value of λmax for this peak depends on the number of π bonds that are conjugated. As the number of conjugated π bonds increases, the value of the longest-wavelength λmax increases.

Expert Solution & Answer
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Answer to Problem 15.7YT

The value of longest-wavelength λmax increases with the number of conjugated double bonds in the compound.

Explanation of Solution

The compounds from Table 15-1 that contain only C and H, the number of conjugated double bonds in them and their longest-wavelength λmax values are

Compound Conjugated π bonds λmax (nm) Compound Conjugated π bonds λmax (nm)
Alkanes, cycloalkanes 0 < 150 EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 15, Problem 15.7YT , additional homework tip  1 2 223
EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 15, Problem 15.7YT , additional homework tip  2 0 161 EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 15, Problem 15.7YT , additional homework tip  3 2 223.5
EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 15, Problem 15.7YT , additional homework tip  4 0 177 EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 15, Problem 15.7YT , additional homework tip  5 2 224
EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 15, Problem 15.7YT , additional homework tip  6 0 178 EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 15, Problem 15.7YT , additional homework tip  7 2 239
EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 15, Problem 15.7YT , additional homework tip  8 0 182 EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 15, Problem 15.7YT , additional homework tip  9 2 256
EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 15, Problem 15.7YT , additional homework tip  10 0 185 EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 15, Problem 15.7YT , additional homework tip  11 3 274
EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 15, Problem 15.7YT , additional homework tip  12 2 217 EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 15, Problem 15.7YT , additional homework tip  13 4 290
EBK ORGANIC CHEMISTRY: PRINCIPLES AND M, Chapter 15, Problem 15.7YT , additional homework tip  14 11 455

For compounds that contain only one double/triple bond – ethene, hex-1-ene, cyclohexene, and hex-1-yne– the longest-wavelength λmax is about 180 nm or less. It is about the same for the non-conjugated compound penta-1, 4-diene. For compounds with two conjugated π bonds – buta-1, 3-diene, cis and trans penta-1, 3-diene, methylbuta-1, 3-diene, cyclopentadiene, and cyclohexa-1, 3-diene – it is about 225 nm. For hexa-1, 3, 5-triene with three conjugated double bonds, it is 274 nm. For octa-1, 3, 5, 7-tetraene with four conjugated double bonds, it is 290 nm. Finally, for β-carotene which has eleven conjugated double bonds, it is 450 nm.

As the number of conjugated π bonds increases, the energy gap between HOMO and LUMO decreases. Consequently, the value of the longest-wavelength λmax increases.

Conclusion

The value of the longest-wavelength λmax depends on the number of π bonds in the conjugated π system.

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Chapter 15 Solutions

EBK ORGANIC CHEMISTRY: PRINCIPLES AND M

Ch. 15 - Prob. 15.11PCh. 15 - Prob. 15.12PCh. 15 - Prob. 15.13PCh. 15 - Prob. 15.14PCh. 15 - Prob. 15.15PCh. 15 - Prob. 15.16PCh. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - Prob. 15.19PCh. 15 - Prob. 15.20PCh. 15 - Prob. 15.21PCh. 15 - Prob. 15.22PCh. 15 - Prob. 15.23PCh. 15 - Prob. 15.24PCh. 15 - Prob. 15.25PCh. 15 - Prob. 15.26PCh. 15 - Prob. 15.27PCh. 15 - Prob. 15.28PCh. 15 - Prob. 15.29PCh. 15 - Prob. 15.30PCh. 15 - Prob. 15.31PCh. 15 - Prob. 15.32PCh. 15 - Prob. 15.33PCh. 15 - Prob. 15.34PCh. 15 - Prob. 15.35PCh. 15 - Prob. 15.36PCh. 15 - Prob. 15.37PCh. 15 - Prob. 15.38PCh. 15 - Prob. 15.39PCh. 15 - Prob. 15.40PCh. 15 - Prob. 15.41PCh. 15 - Prob. 15.42PCh. 15 - Prob. 15.43PCh. 15 - Prob. 15.44PCh. 15 - Prob. 15.45PCh. 15 - Prob. 15.46PCh. 15 - Prob. 15.47PCh. 15 - Prob. 15.48PCh. 15 - Prob. 15.49PCh. 15 - Prob. 15.50PCh. 15 - Prob. 15.51PCh. 15 - Prob. 15.52PCh. 15 - Prob. 15.53PCh. 15 - Prob. 15.54PCh. 15 - Prob. 15.55PCh. 15 - Prob. 15.56PCh. 15 - Prob. 15.57PCh. 15 - Prob. 15.58PCh. 15 - Prob. 15.59PCh. 15 - Prob. 15.60PCh. 15 - Prob. 15.61PCh. 15 - Prob. 15.62PCh. 15 - Prob. 15.63PCh. 15 - Prob. 15.64PCh. 15 - Prob. 15.65PCh. 15 - Prob. 15.66PCh. 15 - Prob. 15.67PCh. 15 - Prob. 15.68PCh. 15 - Prob. 15.1YTCh. 15 - Prob. 15.2YTCh. 15 - Prob. 15.3YTCh. 15 - Prob. 15.4YTCh. 15 - Prob. 15.5YTCh. 15 - Prob. 15.6YTCh. 15 - Prob. 15.7YTCh. 15 - Prob. 15.8YTCh. 15 - Prob. 15.9YTCh. 15 - Prob. 15.10YTCh. 15 - Prob. 15.11YTCh. 15 - Prob. 15.12YTCh. 15 - Prob. 15.13YTCh. 15 - Prob. 15.14YTCh. 15 - Prob. 15.15YTCh. 15 - Prob. 15.16YTCh. 15 - Prob. 15.17YTCh. 15 - Prob. 15.18YTCh. 15 - Prob. 15.19YTCh. 15 - Prob. 15.20YTCh. 15 - Prob. 15.21YTCh. 15 - Prob. 15.22YTCh. 15 - Prob. 15.23YTCh. 15 - Prob. 15.24YTCh. 15 - Prob. 15.25YTCh. 15 - Prob. 15.26YTCh. 15 - Prob. 15.27YTCh. 15 - Prob. 15.28YTCh. 15 - Prob. 15.29YTCh. 15 - Prob. 15.30YT
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