CHEMISTRY:MOLECULAR...(LL)-W/CONNECT
9th Edition
ISBN: 9781264094202
Author: SILBERBERG
Publisher: MCG
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Question
Chapter 15, Problem 15.33P
Interpretation Introduction
Interpretation:
The structure of BHT (Butylated hydroxytoluene) has to be drawn.
Concept Introduction:
Butylated hydroxytoluene is the common preservative used for the cereals and other dry foods.
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3. Consider the compounds below and determine if they are aromatic, antiaromatic, or
non-aromatic. In case of aromatic or anti-aromatic, please indicate number of I
electrons in the respective systems. (Hint: 1. Not all lone pair electrons were explicitly
drawn and you should be able to tell that the bonding electrons and lone pair electrons
should reside in which hybridized atomic orbital 2. You should consider ring strain-
flexibility and steric repulsion that facilitates adoption of aromaticity or avoidance of anti-
aromaticity)
H H
N
N:
NH2
N
Aromaticity
(Circle)
Aromatic Aromatic Aromatic Aromatic Aromatic
Antiaromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic
nonaromatic nonaromatic nonaromatic nonaromatic nonaromatic
aromatic TT
electrons
Me
H
Me
Aromaticity
(Circle)
Aromatic Aromatic Aromatic
Aromatic Aromatic
Antiaromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic
nonaromatic nonaromatic nonaromatic nonaromatic nonaromatic
aromatic πT
electrons
H
HH…
A chemistry graduate student is studying the rate of this reaction:
2 HI (g) →H2(g) +12(g)
She fills a reaction vessel with HI and measures its concentration as the reaction proceeds:
time
(minutes)
[IH]
0
0.800M
1.0
0.301 M
2.0
0.185 M
3.0
0.134M
4.0
0.105 M
Use this data to answer the following questions.
Write the rate law for this reaction.
rate
= 0
Calculate the value of the rate constant k.
k =
Round your answer to 2 significant digits. Also be
sure your answer has the correct unit symbol.
Chapter 15 Solutions
CHEMISTRY:MOLECULAR...(LL)-W/CONNECT
Ch. 15.2 - Prob. 15.1AFPCh. 15.2 - Prob. 15.1BPCh. 15.2 - Prob. 15.2APCh. 15.2 - Prob. 15.2BPCh. 15.2 - How many peaks appear in the NMR spectrum of each...Ch. 15.2 - Prob. B15.2PCh. 15.2 - Prob. B15.3PCh. 15.3 - Prob. 15.3AFPCh. 15.3 - Prob. 15.3BFPCh. 15.4 - Prob. 15.4AFP
Ch. 15.4 - Prob. 15.4BFPCh. 15.4 - Prob. 15.5AFPCh. 15.4 - Prob. 15.5BFPCh. 15.4 - Prob. 15.6AFPCh. 15.4 - Prob. 15.6BFPCh. 15.4 - Prob. 15.7AFPCh. 15.4 - Prob. 15.7BFPCh. 15.6 - Prob. 15.4PCh. 15.6 - Prob. 15.5PCh. 15 - Prob. 15.1PCh. 15 - Prob. 15.2PCh. 15 - Prob. 15.3PCh. 15 - Silicon lies just below carbon in Group 4A(14) and...Ch. 15 - What is the range of oxidation states for carbon?...Ch. 15 - Prob. 15.6PCh. 15 - Prob. 15.7PCh. 15 - Define each type of isomer: (a) constitutional;...Ch. 15 - Prob. 15.9PCh. 15 - Prob. 15.10PCh. 15 - Prob. 15.11PCh. 15 - How does an aromatic hydrocarbon differ from a...Ch. 15 - Prob. 15.13PCh. 15 - Prob. 15.14PCh. 15 - Prob. 15.15PCh. 15 - Prob. 15.16PCh. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - Prob. 15.19PCh. 15 - Prob. 15.20PCh. 15 - Prob. 15.21PCh. 15 - Prob. 15.22PCh. 15 - Prob. 15.23PCh. 15 - Prob. 15.24PCh. 15 - Draw structures from the following names, and...Ch. 15 - Prob. 15.26PCh. 15 - Prob. 15.27PCh. 15 - Prob. 15.28PCh. 15 - Prob. 15.29PCh. 15 - Prob. 15.30PCh. 15 - Prob. 15.31PCh. 15 - Prob. 15.32PCh. 15 - Prob. 15.33PCh. 15 - Prob. 15.34PCh. 15 - Prob. 15.35PCh. 15 - Prob. 15.36PCh. 15 - Prob. 15.37PCh. 15 - Prob. 15.38PCh. 15 - Prob. 15.39PCh. 15 - Prob. 15.40PCh. 15 - Determine the type of each of the following...Ch. 15 - Prob. 15.42PCh. 15 - Prob. 15.43PCh. 15 - Prob. 15.44PCh. 15 - Prob. 15.45PCh. 15 - Prob. 15.46PCh. 15 - Prob. 15.47PCh. 15 - Prob. 15.48PCh. 15 - Prob. 15.49PCh. 15 - Prob. 15.50PCh. 15 - Prob. 15.51PCh. 15 - Prob. 15.52PCh. 15 - Prob. 15.53PCh. 15 - Prob. 15.54PCh. 15 - Prob. 15.55PCh. 15 - Prob. 15.56PCh. 15 - Prob. 15.57PCh. 15 - Prob. 15.58PCh. 15 - Prob. 15.59PCh. 15 - Prob. 15.60PCh. 15 - Prob. 15.61PCh. 15 - Prob. 15.62PCh. 15 - Prob. 15.63PCh. 15 - Prob. 15.64PCh. 15 - Prob. 15.65PCh. 15 - Prob. 15.66PCh. 15 - Prob. 15.67PCh. 15 - Prob. 15.68PCh. 15 - Prob. 15.69PCh. 15 - Prob. 15.70PCh. 15 - Prob. 15.71PCh. 15 - Prob. 15.72PCh. 15 - Prob. 15.73PCh. 15 - Prob. 15.74PCh. 15 - Prob. 15.75PCh. 15 - Prob. 15.76PCh. 15 - Prob. 15.77PCh. 15 - Prob. 15.78PCh. 15 - Prob. 15.79PCh. 15 - Prob. 15.80PCh. 15 - Prob. 15.81PCh. 15 - Prob. 15.82PCh. 15 - Prob. 15.83PCh. 15 - Prob. 15.84PCh. 15 - Prob. 15.85PCh. 15 - Prob. 15.86PCh. 15 - Prob. 15.87PCh. 15 - What is the key structural difference between...Ch. 15 - Protein shape, function, and amino acid sequence...Ch. 15 - What linkage joins the monomers in each strand of...Ch. 15 - What is base pairing? How does it pertain to DNA...Ch. 15 - RNA base sequence, protein amino acid sequence,...Ch. 15 - Prob. 15.93PCh. 15 - Prob. 15.94PCh. 15 - Draw the structure of each of the following...Ch. 15 - Prob. 15.96PCh. 15 - Write the sequence of the complementary DNA strand...Ch. 15 - Prob. 15.98PCh. 15 - Prob. 15.99PCh. 15 - Prob. 15.100PCh. 15 - Prob. 15.101PCh. 15 - Amino acids have an average molar mass of 100...Ch. 15 - Prob. 15.103PCh. 15 - Prob. 15.104PCh. 15 - Some of the most useful compounds for organic...Ch. 15 - Prob. 15.106PCh. 15 - Prob. 15.107PCh. 15 - Prob. 15.108PCh. 15 - Prob. 15.109PCh. 15 - Prob. 15.110PCh. 15 - Prob. 15.111PCh. 15 - Prob. 15.112PCh. 15 - The polypeptide chain in proteins does not exhibit...Ch. 15 - Prob. 15.114PCh. 15 - Prob. 15.115PCh. 15 - Prob. 15.116PCh. 15 - Prob. 15.117PCh. 15 - Wastewater from a cheese factory has the following...Ch. 15 - Prob. 15.119P
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- 1. For the four structures provided, Please answer the following questions in the table below. a. Please draw π molecular orbital diagram (use the polygon-and-circle method if appropriate) and fill electrons in each molecular orbital b. Please indicate the number of π electrons c. Please indicate if each molecule provided is anti-aromatic, aromatic, or non- aromatic TT MO diagram Number of π e- Aromaticity Evaluation (X choose one) Non-aromatic Aromatic Anti-aromatic || ||| + IVarrow_forward1.3 grams of pottasium iodide is placed in 100 mL of o.11 mol/L lead nitrate solution. At room temperature, lead iodide has a Ksp of 4.4x10^-9. How many moles of precipitate will form?arrow_forwardQ3: Circle the molecules that are optically active: ДДДДarrow_forward
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