EBK GET READY FOR ORGANIC CHEMISTRY
2nd Edition
ISBN: 9780321830555
Author: KARTY
Publisher: VST
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Chapter 15, Problem 15.29YT
Interpretation Introduction
Interpretation:
The number of hydrogen atoms in a completely saturated compound with six carbon atoms and one nitrogen atom is to be determined. The consistency of this with unknown 3 having IHD of 4 is to be checked.
Concept introduction:
In a saturated molecule, each carbon has four bonds, and each nitrogen has three bonds. Therefore, a completely saturated molecule with six carbon and one nitrogen would have fifteen hydrogen atoms.
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Using reaction free energy to predict equilibrium composition
Consider the following equilibrium:
2NO2 (g) = N2O4(g)
AGº = -5.4 kJ
Now suppose a reaction vessel is filled with 4.53 atm of dinitrogen tetroxide (N2O4) at 279. °C. Answer the following questions about this system:
Under these conditions, will the pressure of N2O4 tend to rise or fall?
Is it possible to reverse this tendency by adding NO2?
In other words, if you said the pressure of N2O4 will tend to rise, can that
be changed to a tendency to fall by adding NO2? Similarly, if you said the
pressure of N2O4 will tend to fall, can that be changed to a tendency to
'2'
rise by adding NO2?
If you said the tendency can be reversed in the second question, calculate
the minimum pressure of NO 2 needed to reverse it.
Round your answer to 2 significant digits.
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rise
☐ x10
fall
yes
no
☐ atm
G
Ar
1
Why do we analyse salt?
Curved arrows are used to illustrate the flow of electrons. Using
the provided starting and product structures, draw the curved
electron-pushing arrows for the following reaction or
mechanistic step(s).
Be sure to account for all bond-breaking and bond-making
steps.
H
H
CH3OH, H+
H
Select to Add Arrows
H°
0:0
'H
+
Q
HH
■ Select to Add Arrows
CH3OH,
H*
H.
H
CH3OH, H+
HH
■ Select to Add Arrows i
Please select a drawing or reagent from the question area
Chapter 15 Solutions
EBK GET READY FOR ORGANIC CHEMISTRY
Ch. 15 - Prob. 15.1PCh. 15 - Prob. 15.2PCh. 15 - Prob. 15.3PCh. 15 - Prob. 15.4PCh. 15 - Prob. 15.5PCh. 15 - Prob. 15.6PCh. 15 - Prob. 15.7PCh. 15 - Prob. 15.8PCh. 15 - Prob. 15.9PCh. 15 - Prob. 15.10P
Ch. 15 - Prob. 15.11PCh. 15 - Prob. 15.12PCh. 15 - Prob. 15.13PCh. 15 - Prob. 15.14PCh. 15 - Prob. 15.15PCh. 15 - Prob. 15.16PCh. 15 - Prob. 15.17PCh. 15 - Prob. 15.18PCh. 15 - Prob. 15.19PCh. 15 - Prob. 15.20PCh. 15 - Prob. 15.21PCh. 15 - Prob. 15.22PCh. 15 - Prob. 15.23PCh. 15 - Prob. 15.24PCh. 15 - Prob. 15.25PCh. 15 - Prob. 15.26PCh. 15 - Prob. 15.27PCh. 15 - Prob. 15.28PCh. 15 - Prob. 15.29PCh. 15 - Prob. 15.30PCh. 15 - Prob. 15.31PCh. 15 - Prob. 15.32PCh. 15 - Prob. 15.33PCh. 15 - Prob. 15.34PCh. 15 - Prob. 15.35PCh. 15 - Prob. 15.36PCh. 15 - Prob. 15.37PCh. 15 - Prob. 15.38PCh. 15 - Prob. 15.39PCh. 15 - Prob. 15.40PCh. 15 - Prob. 15.41PCh. 15 - Prob. 15.42PCh. 15 - Prob. 15.43PCh. 15 - Prob. 15.44PCh. 15 - Prob. 15.45PCh. 15 - Prob. 15.46PCh. 15 - Prob. 15.47PCh. 15 - Prob. 15.48PCh. 15 - Prob. 15.49PCh. 15 - Prob. 15.50PCh. 15 - Prob. 15.51PCh. 15 - Prob. 15.52PCh. 15 - Prob. 15.53PCh. 15 - Prob. 15.54PCh. 15 - Prob. 15.55PCh. 15 - Prob. 15.56PCh. 15 - Prob. 15.57PCh. 15 - Prob. 15.58PCh. 15 - Prob. 15.59PCh. 15 - Prob. 15.60PCh. 15 - Prob. 15.61PCh. 15 - Prob. 15.62PCh. 15 - Prob. 15.63PCh. 15 - Prob. 15.64PCh. 15 - Prob. 15.65PCh. 15 - Prob. 15.66PCh. 15 - Prob. 15.67PCh. 15 - Prob. 15.68PCh. 15 - Prob. 15.1YTCh. 15 - Prob. 15.2YTCh. 15 - Prob. 15.3YTCh. 15 - Prob. 15.4YTCh. 15 - Prob. 15.5YTCh. 15 - Prob. 15.6YTCh. 15 - Prob. 15.7YTCh. 15 - Prob. 15.8YTCh. 15 - Prob. 15.9YTCh. 15 - Prob. 15.10YTCh. 15 - Prob. 15.11YTCh. 15 - Prob. 15.12YTCh. 15 - Prob. 15.13YTCh. 15 - Prob. 15.14YTCh. 15 - Prob. 15.15YTCh. 15 - Prob. 15.16YTCh. 15 - Prob. 15.17YTCh. 15 - Prob. 15.18YTCh. 15 - Prob. 15.19YTCh. 15 - Prob. 15.20YTCh. 15 - Prob. 15.21YTCh. 15 - Prob. 15.22YTCh. 15 - Prob. 15.23YTCh. 15 - Prob. 15.24YTCh. 15 - Prob. 15.25YTCh. 15 - Prob. 15.26YTCh. 15 - Prob. 15.27YTCh. 15 - Prob. 15.28YTCh. 15 - Prob. 15.29YTCh. 15 - Prob. 15.30YT
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