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Science Chemistry EBK GET READY FOR ORGANIC CHEMISTRY

Which spectrum, 5 or 6 , is more likely for a compound that contains a C=C double bond, is to be explained. Concept introduction: IR spectroscopy enables us to identify different functional groups in the molecule. One of the greatest advantages of IR spectroscopy is that the frequency of a particular type of vibration is typically found within a characteristic range of frequencies, regardless of the functional group with which the vibration is associated. The fact that absorptions by certain vibrations appear with characteristic frequency ranges enables us to use IR spectroscopy to obtain structural information about a molecule. The absorption band for alkene C=C bond appears as a single peak in the range of 1620 – 1680 cm − 1 . Alkene sp 2 C − H appears between 3000 − 3100 cm − 1 .

Which spectrum, 5 or 6 , is more likely for a compound that contains a C=C double bond, is to be explained. Concept introduction: IR spectroscopy enables us to identify different functional groups in the molecule. One of the greatest advantages of IR spectroscopy is that the frequency of a particular type of vibration is typically found within a characteristic range of frequencies, regardless of the functional group with which the vibration is associated. The fact that absorptions by certain vibrations appear with characteristic frequency ranges enables us to use IR spectroscopy to obtain structural information about a molecule. The absorption band for alkene C=C bond appears as a single peak in the range of 1620 – 1680 cm − 1 . Alkene sp 2 C − H appears between 3000 − 3100 cm − 1 .

Solution Summary: The author explains that IR spectroscopy enables us to identify different functional groups in the molecule.

EBK GET READY FOR ORGANIC CHEMISTRY

EBK GET READY FOR ORGANIC CHEMISTRY

2nd Edition

ISBN: 9780321830555

Author: KARTY

Publisher: VST

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Concept explainers

Analyzing and Predicting Spectroscopic Data

The interaction of electromagnetic radiation with the structure of molecules in the sample and their study is referred spectroscopy. Several spectroscopic methods are used to acquire sample information, and these methods are proved to be accurate, fast, …

Question

Chapter 15, Problem 15.25P

Interpretation Introduction

Interpretation:

Which spectrum, 5 or 6, is more likely for a compound that contains a C=C double bond, is to be explained.

Concept introduction:

IR spectroscopy enables us to identify different functional groups in the molecule.

One of the greatest advantages of IR spectroscopy is that the frequency of a particular type of vibration is typically found within a characteristic range of frequencies, regardless of the functional group with which the vibration is associated. The fact that absorptions by certain vibrations appear with characteristic frequency ranges enables us to use IR spectroscopy to obtain structural information about a molecule. The absorption band for alkene C=C bond appears as a single peak in the range of 1620–1680 cm−1. Alkene sp2C−H appears between 3000−3100 cm−1.

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Chapter 15, Problem 15.24P

Chapter 15, Problem 15.26P

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Chapter 15 Solutions

EBK GET READY FOR ORGANIC CHEMISTRY

Ch. 15 - Prob. 15.1P Ch. 15 - Prob. 15.2P Ch. 15 - Prob. 15.3P Ch. 15 - Prob. 15.4P Ch. 15 - Prob. 15.5P Ch. 15 - Prob. 15.6P Ch. 15 - Prob. 15.7P Ch. 15 - Prob. 15.8P Ch. 15 - Prob. 15.9P Ch. 15 - Prob. 15.10P

Ch. 15 - Prob. 15.11P Ch. 15 - Prob. 15.12P Ch. 15 - Prob. 15.13P Ch. 15 - Prob. 15.14P Ch. 15 - Prob. 15.15P Ch. 15 - Prob. 15.16P Ch. 15 - Prob. 15.17P Ch. 15 - Prob. 15.18P Ch. 15 - Prob. 15.19P Ch. 15 - Prob. 15.20P Ch. 15 - Prob. 15.21P Ch. 15 - Prob. 15.22P Ch. 15 - Prob. 15.23P Ch. 15 - Prob. 15.24P Ch. 15 - Prob. 15.25P Ch. 15 - Prob. 15.26P Ch. 15 - Prob. 15.27P Ch. 15 - Prob. 15.28P Ch. 15 - Prob. 15.29P Ch. 15 - Prob. 15.30P Ch. 15 - Prob. 15.31P Ch. 15 - Prob. 15.32P Ch. 15 - Prob. 15.33P Ch. 15 - Prob. 15.34P Ch. 15 - Prob. 15.35P Ch. 15 - Prob. 15.36P Ch. 15 - Prob. 15.37P Ch. 15 - Prob. 15.38P Ch. 15 - Prob. 15.39P Ch. 15 - Prob. 15.40P Ch. 15 - Prob. 15.41P Ch. 15 - Prob. 15.42P Ch. 15 - Prob. 15.43P Ch. 15 - Prob. 15.44P Ch. 15 - Prob. 15.45P Ch. 15 - Prob. 15.46P Ch. 15 - Prob. 15.47P Ch. 15 - Prob. 15.48P Ch. 15 - Prob. 15.49P Ch. 15 - Prob. 15.50P Ch. 15 - Prob. 15.51P Ch. 15 - Prob. 15.52P Ch. 15 - Prob. 15.53P Ch. 15 - Prob. 15.54P Ch. 15 - Prob. 15.55P Ch. 15 - Prob. 15.56P Ch. 15 - Prob. 15.57P Ch. 15 - Prob. 15.58P Ch. 15 - Prob. 15.59P Ch. 15 - Prob. 15.60P Ch. 15 - Prob. 15.61P Ch. 15 - Prob. 15.62P Ch. 15 - Prob. 15.63P Ch. 15 - Prob. 15.64P Ch. 15 - Prob. 15.65P Ch. 15 - Prob. 15.66P Ch. 15 - Prob. 15.67P Ch. 15 - Prob. 15.68P Ch. 15 - Prob. 15.1YT Ch. 15 - Prob. 15.2YT Ch. 15 - Prob. 15.3YT Ch. 15 - Prob. 15.4YT Ch. 15 - Prob. 15.5YT Ch. 15 - Prob. 15.6YT Ch. 15 - Prob. 15.7YT Ch. 15 - Prob. 15.8YT Ch. 15 - Prob. 15.9YT Ch. 15 - Prob. 15.10YT Ch. 15 - Prob. 15.11YT Ch. 15 - Prob. 15.12YT Ch. 15 - Prob. 15.13YT Ch. 15 - Prob. 15.14YT Ch. 15 - Prob. 15.15YT Ch. 15 - Prob. 15.16YT Ch. 15 - Prob. 15.17YT Ch. 15 - Prob. 15.18YT Ch. 15 - Prob. 15.19YT Ch. 15 - Prob. 15.20YT Ch. 15 - Prob. 15.21YT Ch. 15 - Prob. 15.22YT Ch. 15 - Prob. 15.23YT Ch. 15 - Prob. 15.24YT Ch. 15 - Prob. 15.25YT Ch. 15 - Prob. 15.26YT Ch. 15 - Prob. 15.27YT Ch. 15 - Prob. 15.28YT Ch. 15 - Prob. 15.29YT Ch. 15 - Prob. 15.30YT

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