The surface energy required to change a spherical drop of water of 3 mm diameter into 3 spheres of 3 × 10 − 3 mm radius has to be determined. Concept Introduction: A molecule inside liquid feels attraction from all directions uniformly, but surface molecules only feel force from inward direction. So, surface molecules of a liquid feel a net inward force and therefore tend to minimize their surface area to minimize the number of molecules on the liquid surface. This inward force is surface tension. Higher the attractive force on molecules, higher will be the surface tension of liquid. The surface tension of a liquid holds the liquid droplet in spherical shape because a sphere has the lowest surface area. For a spherical drop, high surface tension in necessity.

Question

Want to see the full answer?

Answer 1

Question

Chapter 15, Problem 15.28P

Interpretation Introduction

Interpretation:

The surface energy required to change a spherical drop of water of 3 mm diameter into 3 spheres of 3×10−3 mm radius has to be determined.

Concept Introduction:

A molecule inside liquid feels attraction from all directions uniformly, but surface molecules only feel force from inward direction. So, surface molecules of a liquid feel a net inward force and therefore tend to minimize their surface area to minimize the number of molecules on the liquid surface. This inward force is surface tension.

Higher the attractive force on molecules, higher will be the surface tension of liquid. The surface tension of a liquid holds the liquid droplet in spherical shape because a sphere has the lowest surface area. For a spherical drop, high surface tension in necessity.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

1) The isoamyl acetate report requires eight paragraphs - four for comparison of isoamyl alcohol and isoamyl acetate (one paragraph each devoted to MS, HNMR, CNMR and IR) and four for comparison of acetic acid and isoamyl acetate ((one paragraph each devoted to MS, HNMR, CNMR and IR. 2) For MS, the differing masses of molecular ions are a popular starting point. Including a unique fragmentation is important, too. 3) For HNMR, CNMR and IR state the peaks that are different and what makes them different (usually the presence or absence of certain groups). See if you can find two differences (in each set of IR, HNMR and CNMR spectra) due to the presence or absence of a functional group. Include peak locations. Alternatively, you can state a shift of a peak due to a change near a given functional group. Including peak locations for shifted peaks, as well as what these peaks are due to. Ideally, your focus should be on not just identifying the differences but explaining them in terms of…

№3 Fill in the below boxes. HN 1. LAH 2. H3O+ NH2

For the photochemical halogenation reaction below, draw both propagation steps and include the mechanism arrows for each step. H CH ot CH3 CI-CI MM hv of CH H-CI CH3 2nd attempt See Periodic Table See Hint Draw only radical electrons; do not add lone pair electrons. Note that arrows cannot meet in "space," and must end at either bonds or at atoms. 1 i Add the missing curved arrow notation to this propagation step. 20 H ن S F P H CI Br 品